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Bunuel
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Bunuel
On January 1st, the selling price of a car was $A. The price initially increased by X% on February 1st, and then decreased by X% on March 1st, which resulted in an overall decrease in the price of the car by $1,400. What would have been the overall decrease in price had the increase on February 1st and decrease on March 1st been by 2X%??

A) $1,400
B) $2,800
C) $4,200
D) $5,600
E) $11,200

­Please find the solution in the attached image.
Answer = 5600­
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A more simple method would be to consider values of A and X as 100/- and 10% respectively.
Jan 1 - 100/-
Feb 1 - 110/-
Mar 1 - 99/-
Diff 1= 1/-

Now X = 20%;
Jan 1 - 100/-
Feb 1 - 120/-
Mar 1 - 96/-
Diff 2 = 4/-
So, 4 times from previous
Now from question statement,
Diff 1 = 1440
Therefore, Diff 2 has to be Approx 5600
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Bunuel
On January 1st, the selling price of a car was $A. The price initially increased by X% on February 1st, and then decreased by X% on March 1st, which resulted in an overall decrease in the price of the car by $1,400. What would have been the overall decrease in price had the increase on February 1st and decrease on March 1st been by 2X%??

A) $1,400
B) $2,800
C) $4,200
D) $5,600
E) $11,200

Two successive equal percentage changes of x% each, one an increase and the other a decrease lead to a decrease of \(\frac{x^2}{100}\) %.

So we are given that \(\frac{x^2}{100}\)% of A is $1400.

If instead, the increase and decrease is of 2x%, then the overall change will be a decrease of \(\frac{(2x)^2}{100}\) % i.e. \(\frac{4x^2}{100}%\) of A.

Since \(\frac{x^2}{100}\)% of A is 1400, \(\frac{4x^2}{100}\)% of A will be 4*1400 =5,600

Answer (D)
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