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Bunuel
On July 1, 1982, Ms. Fox deposited $10,000 in a new account at the annual interest rate of 12 percent compounded monthly. If no additional deposits or withdrawals were made and if interest was credited on the last day of each month, what was the amount of money in the account on September 1, 1982?

(A) $10,200
(B) $10,201
(C) $11,100
(D) $12,100
(E) $12,544

Given data,
Annual interest rate=12%
monthly interest rate=\(\frac{12}{12}\)=1%

using compound interest formula,

net amount=\(10000(1+\frac{1}{100})^2\)

=10,201
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Bunuel
On July 1, 1982, Ms. Fox deposited $10,000 in a new account at the annual interest rate of 12 percent compounded monthly. If no additional deposits or withdrawals were made and if interest was credited on the last day of each month, what was the amount of money in the account on September 1, 1982?

(A) $10,200
(B) $10,201
(C) $11,100
(D) $12,100
(E) $12,544
The standard compound interest formula is:
A = P × (1 + r/n)^(n × t)
Where:
  • P = 10,000
  • r = 0.12 (12% annual rate)
  • n = 12 (monthly compounding)
  • From July 1 to Sept 1 = 2 monthst = 2/12 = 1/6 year
So,
n × t = 12 × (1/6) = 2 compounding periods
Now plug in:
A = 10,000 × (1 + 0.12/12)2
A = 10,000 × (1.01)2
A = 10,201
Answer: $10,201 (Option B)
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