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Bunuel
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Bunuel
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1. The question asks us to find a possible combination of Simon's and Tyra's scores.

2. Let Ram's, Simon's, and Tyra's scores be equal to R, S, and T respectively.

3. Ram's score was 20% higher than Simon's. This gives us that \(R = 1.2 * S\).

4. Tyra's score was 25% less than Ram's. This gives us that \(T = 0.75 * R\).

5. Using the two equations, we have: \(T = 0.75 * R = 0.75 * 1.2 * S = 0.9S\).

6. The only combination that has this ratio of 10 to 9 is 280 to 252.

7. Our answer will be: Simon's score - 280 and Tyra's score - 252.
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How I approached it:

R = S(1.2)
T= R(.75)

T = {S(1.2).75}
T = S(.9)

Start plugging in, at this point we know that T<S
252 = 280(.9)
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Simon's score: s
Ram's score: (6/5)*s
Tyra's score: (3/4)*(6/5)*s = (9/10)*s

We need Simon's score and Tyra's score from the options that satisfy the above. Tyra's score should be (9/10) of Simon's score.

9/10 is 90% (not very far from 100%). So, Simon's and Tyra's score should be pretty close to each other.

Start with (100,95) and (280, 252).

9/10 of 100 is 90, not 95. Reject (100, 95).
9/10 of 280 is 252. So, we got our answer.

(280, 252).

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