GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 15 Oct 2019, 12:56

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# On the morning of day 1, Suzy began her tracking tour. She plans to re

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
TAGS:

### Hide Tags

Math Expert
Joined: 02 Sep 2009
Posts: 58340
On the morning of day 1, Suzy began her tracking tour. She plans to re  [#permalink]

### Show Tags

02 Oct 2018, 02:38
00:00

Difficulty:

25% (medium)

Question Stats:

74% (01:30) correct 26% (02:02) wrong based on 56 sessions

### HideShow timer Statistics

On the morning of day 1, Suzy began her tracking tour. She plans to return home at the end of the first day on which it rains. If for the first three days of the tour, the probability of rain on each day is 0.25, what is the probability that Suzy will return home at the end of the day 3?

(A) 1/8
(B) 9/64
(C) 27/64
(D) 37/64
(E) 1/64

_________________
Director
Joined: 20 Feb 2015
Posts: 767
Concentration: Strategy, General Management
Re: On the morning of day 1, Suzy began her tracking tour. She plans to re  [#permalink]

### Show Tags

02 Oct 2018, 06:54
Bunuel wrote:
On the morning of day 1, Suzy began her tracking tour. She plans to return home at the end of the first day on which it rains. If for the first three days of the tour, the probability of rain on each day is 0.25, what is the probability that Suzy will return home at the end of the day 3?

(A) 1/8
(B) 9/64
(C) 27/64
(D) 37/64
(E) 1/64

p(rain) = $$\frac{25}{100}$$
p(suzy will return at the end of third day ) = $$\frac{75}{100}$$ *$$\frac{75}{100}$$ * $$\frac{25}{100}$$ = $$\frac{9}{64}$$
B
Re: On the morning of day 1, Suzy began her tracking tour. She plans to re   [#permalink] 02 Oct 2018, 06:54
Display posts from previous: Sort by

# On the morning of day 1, Suzy began her tracking tour. She plans to re

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne