It is currently 22 Sep 2017, 03:12

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

On the number line, r is left to s and t is right to s. So,

  post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
Manager
Manager
avatar
Joined: 21 Aug 2008
Posts: 202

Kudos [?]: 18 [0], given: 0

On the number line, r is left to s and t is right to s. So, [#permalink]

Show Tags

New post 04 Oct 2008, 11:24
00:00
A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

On the number line, r is left to s and t is right to s. So, s is in between r and t.
Is zero half way between r and s?

1. s is to the right of zero.
2. The distance between t and r is the same as the distance between t and -s.

Kudos [?]: 18 [0], given: 0

Manager
Manager
avatar
Joined: 27 Sep 2008
Posts: 76

Kudos [?]: 9 [0], given: 0

Re: DS - number line [#permalink]

Show Tags

New post 04 Oct 2008, 11:41
r<s s<t

r<s<t

(r+s)/2 = 0 ?

(1)

s>0

we know nothing about r

insufficient

(2)

|t-r| = |t+s|

r = -s

sufficient

the answer is (B)

:)

Kudos [?]: 9 [0], given: 0

VP
VP
User avatar
Joined: 30 Jun 2008
Posts: 1033

Kudos [?]: 688 [0], given: 1

Re: DS - number line [#permalink]

Show Tags

New post 04 Oct 2008, 13:12
Greenberg wrote:
r<s s<t

r<s<t

(r+s)/2 = 0 ?

(1)

s>0

we know nothing about r

insufficient

(2)

|t-r| = |t+s|

r = -s

sufficient

the answer is (B)

:)


How do you simplify |t-r| = |t+s| to r = -s ?
_________________

"You have to find it. No one else can find it for you." - Bjorn Borg

Kudos [?]: 688 [0], given: 1

Manager
Manager
avatar
Joined: 27 Sep 2008
Posts: 76

Kudos [?]: 9 [0], given: 0

Re: DS - number line [#permalink]

Show Tags

New post 04 Oct 2008, 13:19
amitdgr wrote:

How do you simplify |t-r| = |t+s| to r = -s ?


you have two scenarios

(1) t-r = t+s

-r = s

r = -s

(2) -(t-r) = -(t+s)

-t+r = -t-s

r = -s

same result for both !

Kudos [?]: 9 [0], given: 0

VP
VP
User avatar
Joined: 30 Jun 2008
Posts: 1033

Kudos [?]: 688 [0], given: 1

Re: DS - number line [#permalink]

Show Tags

New post 04 Oct 2008, 13:24
Greenberg wrote:
amitdgr wrote:

How do you simplify |t-r| = |t+s| to r = -s ?


you have two scenarios

(1) t-r = t+s

-r = s

r = -s

(2) -(t-r) = -(t+s)

-t+r = -t-s

r = -s

same result for both !



Thanks I understand now.

I am sorry if my question sounds trivial.

Say |x-a| = |y-b|

can we have scenarios like x-a = -(y-b) ?
_________________

"You have to find it. No one else can find it for you." - Bjorn Borg

Kudos [?]: 688 [0], given: 1

1 KUDOS received
Manager
Manager
avatar
Joined: 27 Sep 2008
Posts: 76

Kudos [?]: 9 [1], given: 0

Re: DS - number line [#permalink]

Show Tags

New post 04 Oct 2008, 14:08
1
This post received
KUDOS
amitdgr wrote:
Greenberg wrote:
amitdgr wrote:

How do you simplify |t-r| = |t+s| to r = -s ?


you have two scenarios

(1) t-r = t+s

-r = s

r = -s

(2) -(t-r) = -(t+s)

-t+r = -t-s

r = -s

same result for both !



Thanks I understand now.

I am sorry if my question sounds trivial.

Say |x-a| = |y-b|

can we have scenarios like x-a = -(y-b) ?


No - only two scenarios are possible

see attached
Attachments

Absolute Value.pdf [82.34 KiB]
Downloaded 107 times

To download please login or register as a user

Kudos [?]: 9 [1], given: 0

Manager
Manager
avatar
Joined: 21 Aug 2008
Posts: 202

Kudos [?]: 18 [0], given: 0

Re: DS - number line [#permalink]

Show Tags

New post 04 Oct 2008, 18:48
This question is from GMATPrep (1st one). The OA given is not B, but CCCCC. I wonder why...

Kudos [?]: 18 [0], given: 0

VP
VP
User avatar
Joined: 30 Jun 2008
Posts: 1033

Kudos [?]: 688 [0], given: 1

Re: DS - number line [#permalink]

Show Tags

New post 04 Oct 2008, 21:10
Greenberg wrote:
No - only two scenarios are possible

see attached


Thanks for the pdf :) +1
_________________

"You have to find it. No one else can find it for you." - Bjorn Borg

Kudos [?]: 688 [0], given: 1

Manager
Manager
avatar
Joined: 10 Aug 2008
Posts: 75

Kudos [?]: 13 [0], given: 0

Re: DS - number line [#permalink]

Show Tags

New post 05 Oct 2008, 02:25
2nd statement alone is gud enough.

if 0 is halfway in between r & s than only r == -s.

Kudos [?]: 13 [0], given: 0

Manager
Manager
avatar
Joined: 27 Sep 2008
Posts: 76

Kudos [?]: 9 [0], given: 0

Re: DS - number line [#permalink]

Show Tags

New post 05 Oct 2008, 04:33
Richardson wrote:
This question is from GMATPrep (1st one). The OA given is not B, but CCCCC. I wonder why...


can you copy & paste the screenshot.

:(

Kudos [?]: 9 [0], given: 0

SVP
SVP
avatar
Joined: 17 Jun 2008
Posts: 1540

Kudos [?]: 278 [0], given: 0

Re: DS - number line [#permalink]

Show Tags

New post 05 Oct 2008, 13:33
Richardson wrote:
This question is from GMATPrep (1st one). The OA given is not B, but CCCCC. I wonder why...


B is not sufficient. Consider the two number lines below.

r----------0---------s---------t

In this case, 0 is in the middle of r and s.

r---s-----0---t

In this case, 0 is not in the middle of r and s although this line satisfies all the conditions of stmt2 as well as the problem.

Kudos [?]: 278 [0], given: 0

Manager
Manager
avatar
Joined: 12 Feb 2008
Posts: 177

Kudos [?]: 46 [0], given: 0

Re: DS - number line [#permalink]

Show Tags

New post 05 Oct 2008, 16:07
scthakur wrote:
Richardson wrote:
This question is from GMATPrep (1st one). The OA given is not B, but CCCCC. I wonder why...


B is not sufficient. Consider the two number lines below.

r----------0---------s---------t

In this case, 0 is in the middle of r and s.

r---s-----0---t

In this case, 0 is not in the middle of r and s although this line satisfies all the conditions of stmt2 as well as the problem.


r---s-----0---t does not satisfy S2.

Kudos [?]: 46 [0], given: 0

Current Student
avatar
Joined: 28 Dec 2004
Posts: 3354

Kudos [?]: 316 [0], given: 2

Location: New York City
Schools: Wharton'11 HBS'12
Re: DS - number line [#permalink]

Show Tags

New post 05 Oct 2008, 21:19
I got B too..

can the poster please cut and paste the gmatprep question..

i am not sure but this questions OA might be wrong..

lets look at 2)

r--s----t

we dont know if 0 is between r and s or not...

r---s---t

distance btw r-----t is the same as -s-----t

which means 0 is btw r------0------s (and is exactly half way in between r and s)..

I would like to see a screen shot of the gmatprep question..maybe the OA is wrong or the poster posted something wrong..

Kudos [?]: 316 [0], given: 2

Director
Director
avatar
Joined: 27 May 2008
Posts: 541

Kudos [?]: 354 [0], given: 0

Re: DS - number line [#permalink]

Show Tags

New post 05 Oct 2008, 23:09
i think OA is correct

statement 2 : |t-r| = |t+s|

either t-r = t+s ----> r = -s
OR t-r = -t-s -----> 2t = r-s

consider 2 number lines
r----------0---------s---------t
AND
r--------s---------t---------0, r=-6, s=-4, t=-2

not suff...

Combine 1 and 2 ... suff .. answer C

Kudos [?]: 354 [0], given: 0

Re: DS - number line   [#permalink] 05 Oct 2008, 23:09
Display posts from previous: Sort by

On the number line, r is left to s and t is right to s. So,

  post reply Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.