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Richardson
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On the number line, r is left to s and t is right to s. So, 04 Oct 2008, 11:24
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On the number line, r is left to s and t is right to s. So, s is in between r and t.
Is zero half way between r and s?

1. s is to the right of zero.
2. The distance between t and r is the same as the distance between t and -s.



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On the number line, r is left to s and t is right to s. So, 04 Oct 2008, 11:41
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r<s s<t

r<s<t

(r+s)/2 = 0 ?

(1)

s>0

we know nothing about r

insufficient

(2)

|t-r| = |t+s|

r = -s

sufficient

the answer is (B)

:)
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On the number line, r is left to s and t is right to s. So, 04 Oct 2008, 13:12
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Greenberg
r<s s<t

r<s<t

(r+s)/2 = 0 ?

(1)

s>0

we know nothing about r

insufficient

(2)

|t-r| = |t+s|

r = -s

sufficient

the answer is (B)

:)
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How do you simplify |t-r| = |t+s| to r = -s ?
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On the number line, r is left to s and t is right to s. So, 04 Oct 2008, 13:19
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amitdgr


How do you simplify |t-r| = |t+s| to r = -s ?
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you have two scenarios

(1) t-r = t+s

-r = s

r = -s

(2) -(t-r) = -(t+s)

-t+r = -t-s

r = -s

same result for both !
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On the number line, r is left to s and t is right to s. So, 04 Oct 2008, 13:24
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Greenberg
amitdgr


How do you simplify |t-r| = |t+s| to r = -s ?

you have two scenarios

(1) t-r = t+s

-r = s

r = -s

(2) -(t-r) = -(t+s)

-t+r = -t-s

r = -s

same result for both !
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Thanks I understand now.

I am sorry if my question sounds trivial.

Say |x-a| = |y-b|

can we have scenarios like x-a = -(y-b) ?
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On the number line, r is left to s and t is right to s. So, 04 Oct 2008, 14:08
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amitdgr
Greenberg
amitdgr


How do you simplify |t-r| = |t+s| to r = -s ?

you have two scenarios

(1) t-r = t+s

-r = s

r = -s

(2) -(t-r) = -(t+s)

-t+r = -t-s

r = -s

same result for both !


Thanks I understand now.

I am sorry if my question sounds trivial.

Say |x-a| = |y-b|

can we have scenarios like x-a = -(y-b) ?
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No - only two scenarios are possible

see attached
Attachments

Absolute Value.pdf [82.34 KiB]
Downloaded 160 times

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On the number line, r is left to s and t is right to s. So, 04 Oct 2008, 18:48
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This question is from GMATPrep (1st one). The OA given is not B, but CCCCC. I wonder why...
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On the number line, r is left to s and t is right to s. So, 04 Oct 2008, 21:10
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Greenberg

No - only two scenarios are possible

see attached
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Thanks for the pdf :) +1
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AmitGUPTA
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On the number line, r is left to s and t is right to s. So, 05 Oct 2008, 02:25
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2nd statement alone is gud enough.

if 0 is halfway in between r & s than only r == -s.
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Greenberg
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On the number line, r is left to s and t is right to s. So, 05 Oct 2008, 04:33
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Richardson
This question is from GMATPrep (1st one). The OA given is not B, but CCCCC. I wonder why...
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can you copy & paste the screenshot.

:(
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On the number line, r is left to s and t is right to s. So, 05 Oct 2008, 13:33
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Richardson
This question is from GMATPrep (1st one). The OA given is not B, but CCCCC. I wonder why...
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B is not sufficient. Consider the two number lines below.

r----------0---------s---------t

In this case, 0 is in the middle of r and s.

r---s-----0---t

In this case, 0 is not in the middle of r and s although this line satisfies all the conditions of stmt2 as well as the problem.
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On the number line, r is left to s and t is right to s. So, 05 Oct 2008, 16:07
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scthakur
Richardson
This question is from GMATPrep (1st one). The OA given is not B, but CCCCC. I wonder why...

B is not sufficient. Consider the two number lines below.

r----------0---------s---------t

In this case, 0 is in the middle of r and s.

r---s-----0---t

In this case, 0 is not in the middle of r and s although this line satisfies all the conditions of stmt2 as well as the problem.
Show more

r---s-----0---t does not satisfy S2.
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On the number line, r is left to s and t is right to s. So, 05 Oct 2008, 21:19
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I got B too..

can the poster please cut and paste the gmatprep question..

i am not sure but this questions OA might be wrong..

lets look at 2)

r--s----t

we dont know if 0 is between r and s or not...

r---s---t

distance btw r-----t is the same as -s-----t

which means 0 is btw r------0------s (and is exactly half way in between r and s)..

I would like to see a screen shot of the gmatprep question..maybe the OA is wrong or the poster posted something wrong..
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On the number line, r is left to s and t is right to s. So, 05 Oct 2008, 23:09
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i think OA is correct

statement 2 : |t-r| = |t+s|

either t-r = t+s ----> r = -s
OR t-r = -t-s -----> 2t = r-s

consider 2 number lines
r----------0---------s---------t
AND
r--------s---------t---------0, r=-6, s=-4, t=-2

not suff...

Combine 1 and 2 ... suff .. answer C



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