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On the number line, r is left to s and t is right to s. So,

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Manager
Joined: 21 Aug 2008
Posts: 199
On the number line, r is left to s and t is right to s. So, [#permalink]

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04 Oct 2008, 10:24
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On the number line, r is left to s and t is right to s. So, s is in between r and t.
Is zero half way between r and s?

1. s is to the right of zero.
2. The distance between t and r is the same as the distance between t and -s.
Manager
Joined: 27 Sep 2008
Posts: 76
Re: DS - number line [#permalink]

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04 Oct 2008, 10:41
r<s s<t

r<s<t

(r+s)/2 = 0 ?

(1)

s>0

insufficient

(2)

|t-r| = |t+s|

r = -s

sufficient

VP
Joined: 30 Jun 2008
Posts: 1026
Re: DS - number line [#permalink]

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04 Oct 2008, 12:12
Greenberg wrote:
r<s s<t

r<s<t

(r+s)/2 = 0 ?

(1)

s>0

insufficient

(2)

|t-r| = |t+s|

r = -s

sufficient

How do you simplify |t-r| = |t+s| to r = -s ?
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"You have to find it. No one else can find it for you." - Bjorn Borg

Manager
Joined: 27 Sep 2008
Posts: 76
Re: DS - number line [#permalink]

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04 Oct 2008, 12:19
amitdgr wrote:

How do you simplify |t-r| = |t+s| to r = -s ?

you have two scenarios

(1) t-r = t+s

-r = s

r = -s

(2) -(t-r) = -(t+s)

-t+r = -t-s

r = -s

same result for both !
VP
Joined: 30 Jun 2008
Posts: 1026
Re: DS - number line [#permalink]

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04 Oct 2008, 12:24
Greenberg wrote:
amitdgr wrote:

How do you simplify |t-r| = |t+s| to r = -s ?

you have two scenarios

(1) t-r = t+s

-r = s

r = -s

(2) -(t-r) = -(t+s)

-t+r = -t-s

r = -s

same result for both !

Thanks I understand now.

I am sorry if my question sounds trivial.

Say |x-a| = |y-b|

can we have scenarios like x-a = -(y-b) ?
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"You have to find it. No one else can find it for you." - Bjorn Borg

Manager
Joined: 27 Sep 2008
Posts: 76
Re: DS - number line [#permalink]

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04 Oct 2008, 13:08
1
KUDOS
amitdgr wrote:
Greenberg wrote:
amitdgr wrote:

How do you simplify |t-r| = |t+s| to r = -s ?

you have two scenarios

(1) t-r = t+s

-r = s

r = -s

(2) -(t-r) = -(t+s)

-t+r = -t-s

r = -s

same result for both !

Thanks I understand now.

I am sorry if my question sounds trivial.

Say |x-a| = |y-b|

can we have scenarios like x-a = -(y-b) ?

No - only two scenarios are possible

see attached
Attachments

Absolute Value.pdf [82.34 KiB]

Manager
Joined: 21 Aug 2008
Posts: 199
Re: DS - number line [#permalink]

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04 Oct 2008, 17:48
This question is from GMATPrep (1st one). The OA given is not B, but CCCCC. I wonder why...
VP
Joined: 30 Jun 2008
Posts: 1026
Re: DS - number line [#permalink]

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04 Oct 2008, 20:10
Greenberg wrote:
No - only two scenarios are possible

see attached

Thanks for the pdf +1
_________________

"You have to find it. No one else can find it for you." - Bjorn Borg

Manager
Joined: 10 Aug 2008
Posts: 74
Re: DS - number line [#permalink]

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05 Oct 2008, 01:25
2nd statement alone is gud enough.

if 0 is halfway in between r & s than only r == -s.
Manager
Joined: 27 Sep 2008
Posts: 76
Re: DS - number line [#permalink]

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05 Oct 2008, 03:33
Richardson wrote:
This question is from GMATPrep (1st one). The OA given is not B, but CCCCC. I wonder why...

can you copy & paste the screenshot.

SVP
Joined: 17 Jun 2008
Posts: 1529
Re: DS - number line [#permalink]

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05 Oct 2008, 12:33
Richardson wrote:
This question is from GMATPrep (1st one). The OA given is not B, but CCCCC. I wonder why...

B is not sufficient. Consider the two number lines below.

r----------0---------s---------t

In this case, 0 is in the middle of r and s.

r---s-----0---t

In this case, 0 is not in the middle of r and s although this line satisfies all the conditions of stmt2 as well as the problem.
Manager
Joined: 12 Feb 2008
Posts: 177
Re: DS - number line [#permalink]

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05 Oct 2008, 15:07
scthakur wrote:
Richardson wrote:
This question is from GMATPrep (1st one). The OA given is not B, but CCCCC. I wonder why...

B is not sufficient. Consider the two number lines below.

r----------0---------s---------t

In this case, 0 is in the middle of r and s.

r---s-----0---t

In this case, 0 is not in the middle of r and s although this line satisfies all the conditions of stmt2 as well as the problem.

r---s-----0---t does not satisfy S2.
Current Student
Joined: 28 Dec 2004
Posts: 3342
Location: New York City
Schools: Wharton'11 HBS'12
Re: DS - number line [#permalink]

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05 Oct 2008, 20:19
I got B too..

can the poster please cut and paste the gmatprep question..

i am not sure but this questions OA might be wrong..

lets look at 2)

r--s----t

we dont know if 0 is between r and s or not...

r---s---t

distance btw r-----t is the same as -s-----t

which means 0 is btw r------0------s (and is exactly half way in between r and s)..

I would like to see a screen shot of the gmatprep question..maybe the OA is wrong or the poster posted something wrong..
Director
Joined: 27 May 2008
Posts: 540
Re: DS - number line [#permalink]

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05 Oct 2008, 22:09
i think OA is correct

statement 2 : |t-r| = |t+s|

either t-r = t+s ----> r = -s
OR t-r = -t-s -----> 2t = r-s

consider 2 number lines
r----------0---------s---------t
AND
r--------s---------t---------0, r=-6, s=-4, t=-2

not suff...

Combine 1 and 2 ... suff .. answer C
Re: DS - number line   [#permalink] 05 Oct 2008, 22:09
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