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On the real number line, there are four points P, Q, S, and [#permalink]
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14 Apr 2011, 04:04
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On the real number line, there are four points P, Q, S, and T, with coordinates p, q, s, and t, respectively. Suppose p < q < s < t, p = 1, s = 2. If the distance between P and Q is twice the distance between Q and S, and S is the midpoint of Q and T, then T has coordinate A) 0 B) 1 C) 2 D) 3 E) 4 My answer is I dont have the OA.
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Re: Number line PS [#permalink]
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14 Apr 2011, 04:36
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gmatpapa wrote: On the real number line, there are four points P, Q, S, and T, with coordinates p, q, s, and t, respectively. Suppose p < q < s < t, p = 1, s = 2. If the distance between P and Q is twice the distance between Q and S, and S is the midpoint of Q and T, then T has coordinate A) 0 B) 1 C) 2 D) 3 E) 4 My answer is I dont have the OA. P(p=1)0Q(q=1)S(s=2)T(t=3)p < q < s < t \(PQ+QS=sp=2(1)=3\) distance between P and Q is twice the distance between Q and S\(2QS+QS=3\) \(3QS=3\) \(QS=1\) \(sq=1\) \(2q=1\) \(q=1\) S is the midpoint of Q and T\(QS=ST\) \(sq=ts\) \(21=t2\) \(t=3\) Ans: "D"
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Re: Number line PS [#permalink]
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14 Apr 2011, 04:56
PQST (1) (2) PQ = 2QS QS = ST So Q = 1 TS = QS, So T = 3 Answer  D
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Re: Number line PS [#permalink]
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15 Apr 2011, 20:43
p < q < s < t ______________P_________Q_____S_____T_____ p = 1 and S=2 PQ/QS = 2/1 so Q=1 QS = ST, so T = 3 It is D.
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Re: Number line PS [#permalink]
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16 Apr 2011, 16:05
q+1 = 2(2q) => q = 1
(1+t)/2 = 2 => t =3.
Answer is D.



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Re: Number line PS [#permalink]
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17 Apr 2011, 15:12
need to draw the number line
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Re: Number line PS [#permalink]
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30 Apr 2011, 20:37
p q st 2x x x 1 1 2 3 Hence D.
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Re: Number line PS [#permalink]
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13 Dec 2012, 01:14
Best way is to draw... <pqst> We know p=1 and s=2... <(1)q(2)t> The distance between P and Q is twice the distance of Q and S... SP = 3 = 3x Thus, x=1 SQ=1 2Q=1 Q=1 <(p=1)(q=1)(s=2)t> S is the midpoint of q and t. Thus, t=3 Answer: D
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Re: On the real number line, there are four points P, Q, S, and [#permalink]
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14 Jul 2016, 11:24
gmatpapa wrote: On the real number line, there are four points P, Q, S, and T, with coordinates p, q, s, and t, respectively. Suppose p < q < s < t, p = 1, s = 2. If the distance between P and Q is twice the distance between Q and S, and S is the midpoint of Q and T, then T has coordinate A) 0 B) 1 C) 2 D) 3 E) 4 My answer is I dont have the OA. No fancy mathematics is need here just make a big line and divide it into 4 parts (like we do in a number line) Now since the ascending order is p,q,s,t ; name the parts p,q,s and finally t in the same order p=1 q= unknown, s=2, t= unknown This is the halfway down the question Then the question tells us P to Q=2 Q to S It means p=1 q=1,s=2 {p to q= 1(1)=2; and since s we know is 2 then q to us is 21 =1} S is the average of q and t \(therefore 2=1+\frac{t}{2}\) t+1 =4 t=3 Answer is D
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On the real number line, there are four points P, Q, S, and [#permalink]
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14 Jul 2016, 11:26
gmatpapa wrote: On the real number line, there are four points P, Q, S, and T, with coordinates p, q, s, and t, respectively. Suppose p < q < s < t, p = 1, s = 2. If the distance between P and Q is twice the distance between Q and S, and S is the midpoint of Q and T, then T has coordinate A) 0 B) 1 C) 2 D) 3 E) 4 My answer is I dont have the OA. No fancy mathematics is need here just make a big line and divide it into 4 parts (like we do in a number line) Now since the ascending order is p,q,s,t ; name the parts p,q,s and finally t in the same order p=1 q= unknown, s=2, t= unknown This is the halfway down the question Then the question tells us distance from (P to Q)=twice the distance from (Q to S) It means p=1 q=1,s=2 {p to q= 1(1)=2; and since s we know is 2 then q to us is 21 =1} S is the average of q and t therefore \(S=\frac{q+t}{2}\) therefore \(2=\frac{1+t}{2}\) t+1 =4 t=3 Answer is D
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On the real number line, there are four points P, Q, S, and
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