Last visit was: 14 Jul 2025, 17:58 It is currently 14 Jul 2025, 17:58
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
MathRevolution
User avatar
Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Last visit: 27 Sep 2022
Posts: 10,078
Own Kudos:
18,742
 [15]
Given Kudos: 4
GMAT 1: 760 Q51 V42
GPA: 3.82
Expert
Expert reply
GMAT 1: 760 Q51 V42
Posts: 10,078
Kudos: 18,742
 [15]
Kudos
Add Kudos
15
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
adiagr
Joined: 18 Jan 2010
Last visit: 05 Oct 2019
Posts: 204
Own Kudos:
1,097
 [8]
Given Kudos: 9
GMAT 1: 710 Q48 V40
Posts: 204
Kudos: 1,097
 [8]
6
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
General Discussion
User avatar
chetan2u
User avatar
GMAT Expert
Joined: 02 Aug 2009
Last visit: 14 Jul 2025
Posts: 11,294
Own Kudos:
41,743
 [2]
Given Kudos: 333
Status:Math and DI Expert
Products:
Expert
Expert reply
Posts: 11,294
Kudos: 41,743
 [2]
1
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
User avatar
rohit8865
Joined: 05 Mar 2015
Last visit: 13 Jul 2025
Posts: 817
Own Kudos:
Given Kudos: 45
Products:
Posts: 817
Kudos: 953
Kudos
Add Kudos
Bookmarks
Bookmark this Post
MathRevolution
One ball will drop from a certain height. The height it will reach after rebounding from the floor is 60 percent of the previous height. The total travel is 292cm when it touches the floor on third time. What is the value of the original height?
A. 80cm
B. 90cm
C. 100cm
D. 120cm
E. 130cm

*An answer will be posted in 2 days.
Let the ball dropped from height X cm

total distance in first trip = Xcm
second time bounces back to 60% of X(upwards) and again covers 60% of X(downwards)==2* 60% of X cm
third time also bounces back to 60% of 60% of X(upwards) and again covers 60% of 60%of X(downwards)=2* 60% of 60% of X cm
Given sum of all distance will be 292 cm
X +2*60%of X + 2*60% of 60% of X=292
X=100 cm
Ans C
User avatar
Abhishek009
User avatar
Board of Directors
Joined: 11 Jun 2011
Last visit: 21 Apr 2025
Posts: 5,965
Own Kudos:
5,157
 [2]
Given Kudos: 463
Status:QA & VA Forum Moderator
Location: India
GPA: 3.5
WE:Business Development (Commercial Banking)
Posts: 5,965
Kudos: 5,157
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
MathRevolution
One ball will drop from a certain height. The height it will reach after rebounding from the floor is 60 percent of the previous height.The total travel is 292cm when it touches the floor on third time. What is the value of the original height?
A. 80cm
B. 90cm
C. 100cm
D. 120cm
E. 130cm

*An answer will be posted in 2 days.

Since percentage is rise is mentioned in the question stem it is best to assume , initial height as 100 and proceed ( rest will be easy)

Next draw a mental image of the situation as below -

Attachment:
Falling Ball.png
Falling Ball.png [ 4.34 KiB | Viewed 8184 times ]

First Drop

Falling = 100

Total distance covered in first fall is 100

Second Drop

Rise = 60
Fall = 60

Total distance covered in second fall is 120

Third Drop

Rise = 36
Fall = 36

Total distance covered in second fall is 72

So, the total distance travelled in 292 (100+120+72)


Hence answer will be (C)
User avatar
MathRevolution
User avatar
Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Last visit: 27 Sep 2022
Posts: 10,078
Own Kudos:
Given Kudos: 4
GMAT 1: 760 Q51 V42
GPA: 3.82
Expert
Expert reply
GMAT 1: 760 Q51 V42
Posts: 10,078
Kudos: 18,742
Kudos
Add Kudos
Bookmarks
Bookmark this Post
If we consider the initial height as x, then from x+2(60%)x+2(60%)^2(x)=292, we get x=100. Hence, the correct answer is C.
User avatar
MidhilaMohan
Joined: 03 Mar 2017
Last visit: 22 Oct 2024
Posts: 113
Own Kudos:
Given Kudos: 76
Location: India
GMAT 1: 680 Q49 V34
Products:
GMAT 1: 680 Q49 V34
Posts: 113
Kudos: 69
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Let X be the original height
After first touch it will traverse 0.6x up and 0.6x down
After second touch it will traverse 0.6*0.6x up and the same distance down
Hence total is
X+ 1.2x + 0.72x = 292
X=100
User avatar
MHIKER
Joined: 14 Jul 2010
Last visit: 24 May 2021
Posts: 945
Own Kudos:
Given Kudos: 690
Status:No dream is too large, no dreamer is too small
Concentration: Accounting
Posts: 945
Kudos: 5,460
Kudos
Add Kudos
Bookmarks
Bookmark this Post
MathRevolution
One ball will drop from a certain height. The height it will reach after rebounding from the floor is 60 percent of the previous height. The total travel is 292cm when it touches the floor on third time. What is the value of the original height?
A. 80cm
B. 90cm
C. 100cm
D. 120cm
E. 130cm

*An answer will be posted in 2 days.

Rebounding; the ball go up and come back down.

Let original distance is x cm

\(x+2*0.60x+2*0.60*0.60x=292\)

\(x+1.20x+0.72x=292\)

\(2.92x=292\)

\(x=\frac{292}{2.92}=\frac{292}{292}*100=100\)

The answer is \(C\)
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 37,399
Own Kudos:
Posts: 37,399
Kudos: 1,013
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Moderators:
Math Expert
102570 posts
PS Forum Moderator
691 posts