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One red bottle and three blue bottles are to be arranged in a straight [#permalink]
Since there are 4 slot and only one color is unique that is red so we can place at 4 different places
c is the option
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Re: One red bottle and three blue bottles are to be arranged in a straight [#permalink]
Let the blue bottles be denoted by B and the red bottle be denoted by R

There are 4 combinations possible
BBBR
BBRB
BRBB
RBBB
(Option C)
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Re: One red bottle and three blue bottles are to be arranged in a straight [#permalink]
Can someone explain this in terms of permutations?

I thought this is a permutations question where order matters. And the formula for permutations is Total!/Exclude!

Thanks!
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Re: One red bottle and three blue bottles are to be arranged in a straight [#permalink]
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tittoo wrote:
Can someone explain this in terms of permutations?

I thought this is a permutations question where order matters. And the formula for permutations is Total!/Exclude!

Thanks!



Hi tittoo,

This is a question of arrangement, where n items need to be arranged and c items are similar

The general formula for this is \(\frac{n!}{c!}\)

Hope that helps!
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Re: One red bottle and three blue bottles are to be arranged in a straight [#permalink]
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Bunuel wrote:
One red bottle and three blue bottles are to be arranged in a straight line from left to right on a windowsill. How many different unique arrangements are possible?

A. 12
B. 6
C. 4
D. 3
E. 1


This is a permutation with indistinguishable items problem.

Since there are a total of 4 bottles, in which 3 of them are indistinguishable blue bottles, we can arrange the bottles in 4!/(3!) = 4 ways.

Answer: C
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Re: One red bottle and three blue bottles are to be arranged in a straight [#permalink]
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