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One woman and one man can build a wall together in two hours, but the woman would need the help of two girls in order to complete the same job in the same amount of time. If one man and one girl worked together, it would take them four hours to build the wall. Assuming that rates for men, women and girls remain constant, how many hours would it take one woman, one man, and one girl, working together, to build the wall?

Re: One woman and one man can build a wall together in two hours, but the [#permalink]

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09 Sep 2015, 03:14

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Solution: Let work done by man, women and girl per hour be m,w,g respectively. Then, m+w = 1/2-->(1) , w + 2g = 1/2-->(2) and m + g =1/4-->(3). No. of hours it would take forone woman, one man, and one girl, working together, to build the wall,n = 1/m+w+g From (1) and (2), m=2g and from (3) g=1/12,m=1/6 and w=1/3. So, n = 1/(7/12) = 12/7

One woman and one man can build a wall together in two hours, but the woman would need the help of two girls in order to complete the same job in the same amount of time. If one man and one girl worked together, it would take them four hours to build the wall. Assuming that rates for men, women and girls remain constant, how many hours would it take one woman, one man, and one girl, working together, to build the wall?

This question is certainly quite tricky but if you understand the relation between work and rate, you can still solve this question easily. Mind you, we are using variables here only because I don’t want to write man, woman and girl again and again. Notice that there are no ‘=’ signs i.e. we are not making equations so we are not doing any algebraic manipulations.

The question is long so take one line at a time and analyze it. We will keep condensing the information we get from each sentence and figuring out the implications of new and previous information as we go along.

“One woman and one man can build a wall together in 2 hrs,” 1w + 1m -> 2 hrs ……(I)

“but the woman would need the help of 2 girls in order to complete the same job in the same amount of time.” 1w + 2g -> 2 hrs …..(II)

From (I) and (II), we can say that 1m is equivalent to 2g (i.e. 1 man does the same work as 2 girls do in the same amount of time; 1m ? 2g)

“If 1 man and 1 girl worked together, it would take them four hours to build the wall.” 1m + 1g -> 4hrs (Since 1m ? 2g, we can say that 3g will take 4 hrs to build the wall.) or 2m + 2g -> 2 hrs …..(III) (If number of workers double, time taken to do the work becomes half)

From (II) and (III), 1w ? 2m (i.e. 1 woman does the same work as 2 men do in the same amount of time) Hence, 1w ? 2m ? 4g

“Assuming that rates for women, men and girls remain constant, how many hours would it take 1 woman, 1 man and 1 girl working together to build the wall?” 1w + 1m + 1g ? 4g + 2g + 1g ? 7g. Since 3g take 4 hrs to build the wall, 7g will take 3*4/7 = 12/7 hrs to complete the wall.

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02 Nov 2016, 02:24

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One woman and one man can build a wall together in two hours, but the woman would need the help of two girls in order to complete the same job in the same amount of time. If one man and one girl worked together, it would take them four hours to build the wall. Assuming that rates for men, women and girls remain constant, how many hours would it take one woman, one man, and one girl, working together, to build the wall?

(A) 5/7 (B) 1 (C) 10/7 (D) 12/7 (E) 22/7

Another approach is to determine the size of the job

One woman and one man can build a wall together in two hours, but the woman would need the help of two girls in order to complete the same job in the same amount of time.

The part in blue tells us that 2 girls have the same output as 1 man. So, let's say that 1 girl has an output of 1 unit per hour This means that 1 man has an output of 2 units per hour So, COMBINED, 1 man and 1 girl have an output of 3 units per hour

If one man and one girl worked together, it would take them four hours to build the wall. Working together, 1 man and 1 girl have an output of 3 units per hour So, after 4 hours, their combined output is 12 units. In other words, we can say that the entire job consists of 12 units.

One woman and one man can build a wall together in two hours Since 1 man has an output of 2 units per hour, in two hours the man's output will be 4 units. The entire job consists of 12 units, so the woman completed the other 8 units (in 2 hours). So, 1 woman has an output of 4 units per hour

How many hours would it take one woman, one man, and one girl, working together, to build the wall? We have: 1 girl has an output of 1 unit per hour 1 man has an output of 2 units per hour 1 woman has an output of 4 units per hour And the entire job consists of 12 units.

The combined rate of all 3 workers = 1 + 2 + 4 = 7 units per hour So, the time to complete the job = 12/7 hours

Re: One woman and one man can build a wall together in two hours, but the [#permalink]

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14 Aug 2017, 09:44

A - man B - woman C - girl Then piece of work done per hour 1. (a + b) = ½ 2. (a+c) = ¼ 3. (b+2c) = ½ b=½-a a=¼ +c For the third equation, (½-¼+c+2c)=½ ¼+3c=½ 3c=¼ c=1/12 so one girl's rate is 1/12 Then plug the value of c for others equation and we get a= ⅙ and b = ¼ Then ⅙+ ¼+1/12= 7/12 so get the entire work done then need to work 12/7 hours

One woman and one man can build a wall together in two hours, but the woman would need the help of two girls in order to complete the same job in the same amount of time. If one man and one girl worked together, it would take them four hours to build the wall. Assuming that rates for men, women and girls remain constant, how many hours would it take one woman, one man, and one girl, working together, to build the wall?

(A) 5/7 (B) 1 (C) 10/7 (D) 12/7 (E) 22/7

Kudos for a correct solution.

We can let m = the time is takes the man to build the wall, w = the time it takes the woman to build the wall, and g = the time it takes one girl to build the wall. Looking at the rates of these individuals, we see that one man’s rate is 1/m, one woman’s rate is 1/w, and 1 girl’s rate is 1/g. Thus:

1/m + 1/w = 1/2

and

1/w + 2/g = 1/2

and

1/m + 1/g = 1/4

From the first equation, let’s isolate 1/m:

1/m = 1/2 - 1/w

Let’s substitute this in the equation 1/m + 1/g = 1/4:

1/2 - 1/w + 1/g = 1/4

-1/w + 1/g = -1/4

Adding the equations 1/w + 2/g = 1/2 and -1/w + 1/g = -1/4 together, we obtain:

3/g = 1/4

g = 12

Since it takes a girl 12 hours to finish the job, her rate is 1/12. We are looking for 1/m + 1/w + 1/g; therefore, we add 1/12 to the equation 1/m + 1/w = 1/2:

1/m + 1/w + 1/g = 1/2 + 1/12

1/m + 1/w + 1/g = 7/12

Thus, it will take 1/(7/12) = 12/7 hours for a man, a woman, and a girl to build the wall, working together.

Alternate Solution:

Since the woman can finish the job in the same amount of time with the help of either one man or two girls, the rate of one man is equal to the rate of two girls.

Since one man and one girl can finish the job in 4 hours, and since the rate of one man is equal to the rate of two girls, three girls can finish the job in 4 hours. Since time is inversely proportional to the number of workers, one girl can finish the job in 12 hours.

Since one man and one woman finish the job in two hours, they complete 1/2 of the job in one hour. Since one girl can finish the job in 12 hours, one girl can complete 1/12 of the job in one hour. All working together, they finish 1/2 + 1/12 = 7/12 of the job in one hour. If 7/12 of the job gets done in one hour, then the entire job will get done in 1/(7/12) = 12/7 hours.

Answer: D
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