Bunuel
Operating at their respective constant rates, Photocopying machine B takes 6 minutes more than photocopying machine A to copy x pages. When machines A and B are operated simultaneously, 7x pages can be copied in 20 minutes. In how many minutes can machine A operating alone copy 2x pages?
A. 60/7
B. 8
C. 30/7
D. 4
E. A unique answer cannot be determined
The stem says:
To copy
x pages, machine A takes
M minutes.
To copy
x pages, machine B takes
M + 6 minutes.
To copy
7x pages, machine A and B together take
20 minutes.
This implies that machine A and B together take
\(\frac{20}{7}\) minutes to copy
x pages.
Once we've known the rate of machine A and B working together to complete copying X pages, to find
M, we can use the work rate formula: \(\frac{1}{A} + \frac{1}{B} = \frac{1}{A+B}\)
Plug in the values and then solve the equation to find
M:
\(\frac{1}{M} + \frac{1}{M+6} = \frac{7}{20}\)
\(\frac{M+6+M}{M(6+M)} = \frac{7}{20}\)
\(20(M+6+M) = 7(6M+M^2)\)
\(40M+120 = 42M+7M^2\)
\(7M^2 + 2M - 120 = 0\)
\(7M^2 -28M + 30M - 120 = 0\)
\(7M(M - 4) + 30(M - 4) = 0\)
\(M = 4 ,-\frac{30}{7}\) - time cannot be negative, so we can get rid of the negative value.
Now we know that machine A takes
4 minutes to complete copying
x pages; however, this is not what the question asks.
The question asks "how many minutes does machine A takes to complete copying
2x pages?; so, we need to multiply M by
2.
Therefore, the correct answer is
8 minutes.
PS. I'd like to know whether there are more efficient ways to solve this kind of questions.