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Over a four-game stretch, Dennis's bowling scope average 240. By what

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Over a four-game stretch, Dennis's bowling scope average 240. By what  [#permalink]

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New post 19 Sep 2018, 15:43
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Over a four-game stretch, Dennis's bowling scope average 240. By what percent would his score have had to have been higher in order for him to average a perfect game (300)?
A) 22%
B) 25%
C) 20%
D) 40%
E) 60%
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Re: Over a four-game stretch, Dennis's bowling scope average 240. By what  [#permalink]

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New post 19 Sep 2018, 15:51
My questions:
1) I was lost in the translation of the problem - esp ..."have had to have been..."? What is recommended practice? How do i ensure that i understand the question thoroughly before attempting an answer.
2) Many times, i waste time in rereading the problem again and again. How do i avoid that and ensure i understand the problem in first go itself?

I am not sure if my question make any sense. Appreciate everyone's time here.
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Re: Over a four-game stretch, Dennis's bowling scope average 240. By what  [#permalink]

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New post 15 Nov 2018, 06:28
Top Contributor
Cinematiccuisine wrote:
Over a four-game stretch, Dennis's bowling scope average 240. By what percent would his score have had to have been higher in order for him to average a perfect game (300)?
A) 22%
B) 25%
C) 20%
D) 40%
E) 60%


In other words, an increase from 240 to 300 represents what kind of percent increase?

Percent increase = (100)(new - old)/old
= (100)(300 - 240)/240
= (100)(60)/240
= (100)(1/4)
= 25%

Answer: B

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Brent
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Over a four-game stretch, Dennis's bowling scope average 240. By what  [#permalink]

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New post 15 Nov 2018, 09:41
Cinematiccuisine wrote:
Over a four-game stretch, Dennis's bowling scope average 240. By what percent would his score have had to have been higher in order for him to average a perfect game (300)?
A) 22%
B) 25%
C) 20%
D) 40%
E) 60%


Current Average: 240
Perfect Average: 300

So an increase of 60 average points is required

To calculate increase = \(\frac{Expected Increase}{Current Average}*100\) %
=\(\frac{60}{240}*100\) %
=\(\frac{100}{4}\) %
=25%
Hence B is the correct answer
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Over a four-game stretch, Dennis's bowling scope average 240. By what &nbs [#permalink] 15 Nov 2018, 09:41
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Over a four-game stretch, Dennis's bowling scope average 240. By what

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