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11 Jun 2020, 04:39
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P is the set of positive integers, which are divisible by 2 and less than 200. R be the set of positive integers, which are divisible by 5 and are less than 200. How many subsets of P are also subsets of R?
A. 2^18
B. 2^19 - 1
C. 2^19
D. 2^19 + 1
E. 2^20
Are You Up For the Challenge: 700 Level Questions
A. 2^18
B. 2^19 - 1
C. 2^19
D. 2^19 + 1
E. 2^20
Are You Up For the Challenge: 700 Level Questions
11 Jun 2020, 04:50
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P = ( 2, 4 , 6 .... 198)
R = ( 5 , 10, 15, ....195)
Element of P which are also there in R are (10, 20, 30...190)
For subsets each of these have two choices either to take or not to take so total number of subsets of P which are also subsets of R are 2^19
Option C is the answer.
Posted from my mobile device
R = ( 5 , 10, 15, ....195)
Element of P which are also there in R are (10, 20, 30...190)
For subsets each of these have two choices either to take or not to take so total number of subsets of P which are also subsets of R are 2^19
Option C is the answer.
Posted from my mobile device
yashikaaggarwal
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11 Jun 2020, 05:56
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P = {2,4,6..........198}
R = {5,10,15,20...........195}
Elements if subset of P and R = LCM of 2&5 = (10,20,30......190
An = A+(n-1)*d
190 = 10+(n-1)*10
180 = (n-1)*10
18 = n-1
19 = n -----------(1)
How many subsets of P are also subsets of R = Either taking one no. Or not = 2^19
Answer is C
Posted from my mobile device
R = {5,10,15,20...........195}
Elements if subset of P and R = LCM of 2&5 = (10,20,30......190
An = A+(n-1)*d
190 = 10+(n-1)*10
180 = (n-1)*10
18 = n-1
19 = n -----------(1)
How many subsets of P are also subsets of R = Either taking one no. Or not = 2^19
Answer is C
Posted from my mobile device
