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p, q, r, and s are integers such that p > q > r. what is the value of
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p, q, r, and s are integers such that p > q > r. what is the value of (r + s)? (1) [m]x^4x^2=(xp)(xq)(xr)(xs)[/m] (2) s < q Source : expertsglobalEDIT: A correct DS question will NOT give two different answers through the two statements..
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Originally posted by rishabhmishra on 27 Mar 2018, 22:16.
Last edited by chetan2u on 17 Apr 2018, 07:36, edited 1 time in total.
Flawed question



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Re: p, q, r, and s are integers such that p > q > r. what is the value of
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27 Mar 2018, 22:59
rishabhmishra wrote: Q p,q,r, and s are integers such that p>q>r. what is the value of (r+s)? 1.\(x^4x^2=(xp)(xq)(xr)(xs)\) 2. s<q Source : expertsglobal Statement 1: Lets break down the left hand side into its factors, and then compare it with right hand side. x^4  x^2 = x^2 (x^2  1) = x^2 (x1) (x+1). This can further be written as: x*x*(x1)*(x+1) = (x0)*(x0)*(x1)*(x(1)) (I have written x+1 as x(1) so that I can easily compare it to right hand side) So we have: (x0)*(x0)*(x1)*(x(1)) = (xp)(xq)(xr)(xs) Thus comparing the two sides, we can say that p, q, r, s will take the values of 0, 0, 1 and 1 in some order. And two of them will take the same value of '0'. We are already given that p > q > r. This means p=1, q=0 and r=1; that's the only possibility here. This leaves s=0. So we can calculate r+s = 1+0 = 1. Sufficient. Statement 2: s < q. Clearly this is not sufficient. Hence A answer.



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Re: p, q, r, and s are integers such that p > q > r. what is the value of
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16 Apr 2018, 23:06
amanvermagmat, Bunuel, chetan2uIn this question, statement 1 says s=q. While as per statement 2, s<q. Is it possible to statement contradict each other in GMAT? Please provide insights on the quality of question. amanvermagmat wrote: rishabhmishra wrote: Q p,q,r, and s are integers such that p>q>r. what is the value of (r+s)? 1.\(x^4x^2=(xp)(xq)(xr)(xs)\) 2. s<q Source : expertsglobal Statement 1: Lets break down the left hand side into its factors, and then compare it with right hand side. x^4  x^2 = x^2 (x^2  1) = x^2 (x1) (x+1). This can further be written as: x*x*(x1)*(x+1) = (x0)*(x0)*(x1)*(x(1)) (I have written x+1 as x(1) so that I can easily compare it to right hand side) So we have: (x0)*(x0)*(x1)*(x(1)) = (xp)(xq)(xr)(xs) Thus comparing the two sides, we can say that p, q, r, s will take the values of 0, 0, 1 and 1 in some order. And two of them will take the same value of '0'. We are already given that p > q > r. This means p=1, q=0 and r=1; that's the only possibility here. This leaves s=0. So we can calculate r+s = 1+0 = 1. Sufficient. Statement 2: s < q. Clearly this is not sufficient. Hence A answer.
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Re: p, q, r, and s are integers such that p > q > r. what is the value of
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16 Apr 2018, 23:11
Bunuel chetan2uIs this question acceptable as GMAT question? Statement 1 and Statement 2 are contradicting each other. From Statement 1, we are getting q=s=0 Statement 2 :s < q As per GMATinsight 's earlier comment on below post https://gmatclub.com/forum/inthexyplanelandmaretwolines34isapointonlyon263149.htmlIt is a disqualified question. Quote: a disqualified question as per GMAT standard as statement 1 and 2 are contradictory Please clarify.
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Re: p, q, r, and s are integers such that p > q > r. what is the value of
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16 Apr 2018, 23:20
gmatbusters wrote: amanvermagmat, Bunuel, chetan2uIn this question, statement 1 says s=q. While as per statement 2, s<q. Is it possible to statement contradict each other in GMAT? Please provide insights on the quality of question. amanvermagmat wrote: rishabhmishra wrote: Q p,q,r, and s are integers such that p>q>r. what is the value of (r+s)? 1.\(x^4x^2=(xp)(xq)(xr)(xs)\) 2. s<q Source : expertsglobal Statement 1: Lets break down the left hand side into its factors, and then compare it with right hand side. x^4  x^2 = x^2 (x^2  1) = x^2 (x1) (x+1). This can further be written as: x*x*(x1)*(x+1) = (x0)*(x0)*(x1)*(x(1)) (I have written x+1 as x(1) so that I can easily compare it to right hand side) So we have: (x0)*(x0)*(x1)*(x(1)) = (xp)(xq)(xr)(xs) Thus comparing the two sides, we can say that p, q, r, s will take the values of 0, 0, 1 and 1 in some order. And two of them will take the same value of '0'. We are already given that p > q > r. This means p=1, q=0 and r=1; that's the only possibility here. This leaves s=0. So we can calculate r+s = 1+0 = 1. Sufficient. Statement 2: s < q. Clearly this is not sufficient. Hence A answer. Hello As per my understanding (from reading various Bunuel's posts over past some time) this is a flawed question in that the two statements contradict each other, just as you mentioned. Thanks for raising this point. Maybe Bunuel/Chetan/Karishma would've something to add to this. So if we can just change the second statement slightly to make it consistent with the first statement (lets say we make it s < p instead of s < q), the question can be very easily rectified.




Re: p, q, r, and s are integers such that p > q > r. what is the value of &nbs
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