chetan2u wrote:
GMATinsight wrote:
If a line which has the equation 7x + 17y = 1000 is plotted on X-Y plane then how many points will fall on the line in 1st quadrant which will have both x and y co-ordinates Integers?
A) 6
B) 7
C) 8
D) 9
E) 10
Hi,
First quadrant is the quadrant where both x and y are POSITIVE...
Let's see the equation..
7x+17y=1000
You have to find the first set of x and y that satisfies the equation and thereafter the remaining can be found..
Here subtract multiples of 7 from 1000 and check if remaining amount is div by 17..
When x is 2, y is 58... This is the first set..
Remaining values of y will be 58-7t, where t is integer..
When t is 9, 7t becomes 7*9=63 and 58-7t will become negative..
Hence t<9..
So t will take all values from 0 to 8 so 9 values..
D
GMATinsight pl relook at the OA provided by you. Ans will be 9 and not 10..
So D is the answer and Not E
sir , can you please explain why " Remaining values of y will be 58-7t"
I'm really confused , it took so long for me to answer this question , here's my way :
7x + 17y = 1000
y = (-7x + 1000 )/17
now , + 1000-7x must be divisable by 17 , I'm stuck here , we know that x=<142 but how we can know how many valuse of (-7x + 1000 ) that are divisable by 17 where x=<142 ?
i tried back and forth ,(-7x + 1000 ) can be written as ( 1000+10x -17x )
now , -17x is no problem , let's take care only of 1000+10x which can be written as 10(100+x)
now , since 0=< x =< 142
100=< 100+x =< 242
let's find how many numbers divisable by 17 between 100, 242 in the classic way , the answer is 9
I appreciate any detailed explanation of other methods
Thanks