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06 Dec 2012, 07:06
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Paula and Sandy were among those people who sold raffle tickets to raise money for Club X. If Paula and Sandy sold a total of 100 of the tickets, how many of
the tickets did Paula sell?
(1) Sandy sold 2/3 as many of the raffle tickets as Paula did.
(2) Sandy sold 8 percent of all the raffle tickets sold for Club X.
the tickets did Paula sell?
(1) Sandy sold 2/3 as many of the raffle tickets as Paula did.
(2) Sandy sold 8 percent of all the raffle tickets sold for Club X.
06 Dec 2012, 07:10
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Paula and Sandy were among those people who sold raffle tickets to raise money for Club X. If Paula and Sandy sold a total of 100 of the tickets, how many of the tickets did Paula sell?
Given that \(p+s=100\), where \(p\) and \(s\) are the number of tickets sold by Paula and Sandy, respectively.
(1) Sandy sold 2/3 as many of the raffle tickets as Paula did --> \(s=\frac{2}{3}p\). We have two distinct linear equations with two unknowns (\(p+s=100\) and \(s=\frac{2}{3}p\)), thus we can solve for both of them. Sufficient.
(2) Sandy sold 8 percent of all the raffle tickets sold for Club X --> we don't know the total number of the raffle tickets sold, thus we cannot find \(s\), which means that we cannot find \(p\). Not sufficient.
Answer: A.
Given that \(p+s=100\), where \(p\) and \(s\) are the number of tickets sold by Paula and Sandy, respectively.
(1) Sandy sold 2/3 as many of the raffle tickets as Paula did --> \(s=\frac{2}{3}p\). We have two distinct linear equations with two unknowns (\(p+s=100\) and \(s=\frac{2}{3}p\)), thus we can solve for both of them. Sufficient.
(2) Sandy sold 8 percent of all the raffle tickets sold for Club X --> we don't know the total number of the raffle tickets sold, thus we cannot find \(s\), which means that we cannot find \(p\). Not sufficient.
Answer: A.
General Discussion
17 May 2014, 08:33
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Bunuel
Paula and Sandy were among those people who sold raffle tickets to raise money for Club X. If Paula and Sandy sold a total of 100 of the tickets, how many of the tickets did Paula sell?
Given that \(p+s=100\), where \(p\) and \(s\) are the number of tickets sold by Paula and Sandy, respectively.
(1) Sandy sold 2/3 as many of the raffle tickets as Paula did --> \(s=\frac{2}{3}p\). We have two distinct linear equations with two unknowns (\(p+s=100\) and \(s=\frac{2}{3}p\)), thus we can solve for both of them. Sufficient.
(2) Sandy sold 8 percent of all the raffle tickets sold for Club X --> we don't know the total number of the raffle tickets sold, thus we cannot find \(s\), which means that we cannot find \(p\). Not sufficient.
Answer: A.
Given that \(p+s=100\), where \(p\) and \(s\) are the number of tickets sold by Paula and Sandy, respectively.
(1) Sandy sold 2/3 as many of the raffle tickets as Paula did --> \(s=\frac{2}{3}p\). We have two distinct linear equations with two unknowns (\(p+s=100\) and \(s=\frac{2}{3}p\)), thus we can solve for both of them. Sufficient.
(2) Sandy sold 8 percent of all the raffle tickets sold for Club X --> we don't know the total number of the raffle tickets sold, thus we cannot find \(s\), which means that we cannot find \(p\). Not sufficient.
Answer: A.
I believe the key premise for statement 2 is that there could be others as well who sold tickets for Club X. Right ?
