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04 Feb 2025, 01:30
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
70% (02:19) correct
30%
(02:14)
wrong
based on 180
sessions
History
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Not Attempted Yet
People in a society read three kinds of newspapers, newspaper A or newspaper B or newspaper C. Each house in this society daily receives one copy of one or more of these three newspapers only. How many houses receive newspaper B only?
(1) 50 houses receive copies of either newspaper A or newspaper C, while 18 houses receive copies of exactly two newspapers.
(2) 5 houses receive copies of all three newspapers, and in total 92 copies combined of these three newspapers are received in this society daily.
(1) 50 houses receive copies of either newspaper A or newspaper C, while 18 houses receive copies of exactly two newspapers.
(2) 5 houses receive copies of all three newspapers, and in total 92 copies combined of these three newspapers are received in this society daily.
05 Feb 2025, 02:27
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Use the formula
Total = A + B + C -Both -2(ALL)
Total = A + B + C -Both -2(ALL)
06 Feb 2025, 09:32
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(1) Since 50 households receive A and C newspapers, they cannot be B exclusive, hence "Not B exclusive" is 50, but we do not know the total volume of all newspapers. NOT SUFFICIENT
(2) Gives us the total volume of all newspapers (92) and the overlap of A,B,C but not how much is in B or C total. NOT SUFFICIENT
Combining both gives us:
- 92 newspapers in total
- Of which 50 are "not B exclusive"
- Hence 92-50 = 42 = B exclusive households.
Am i correct or am I missing something?
(2) Gives us the total volume of all newspapers (92) and the overlap of A,B,C but not how much is in B or C total. NOT SUFFICIENT
Combining both gives us:
- 92 newspapers in total
- Of which 50 are "not B exclusive"
- Hence 92-50 = 42 = B exclusive households.
Am i correct or am I missing something?
