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01 Feb 2016, 18:09
Kudos
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Hi, I have a question..
Suppose there are 100 people and there are 100 seats.. Then the possible arrangements are 100!
But if we have two rows or seats 50 each, what will be the number of possible arrangements in that case? is it 100!*2??
Suppose there are 100 people and there are 100 seats.. Then the possible arrangements are 100!
But if we have two rows or seats 50 each, what will be the number of possible arrangements in that case? is it 100!*2??
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02 Feb 2016, 11:06
Kudos
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Hi skyfarer,
Unless you include some additional 'restrictions' to the prompt (or ask a question that is dependent on the fact that there are 2 rows), from a math standpoint, having two rows of 50 is no different from having one row of 100. The total number of permutations would still be 100!
GMAT assassins aren't born, they're made,
Rich
Unless you include some additional 'restrictions' to the prompt (or ask a question that is dependent on the fact that there are 2 rows), from a math standpoint, having two rows of 50 is no different from having one row of 100. The total number of permutations would still be 100!
GMAT assassins aren't born, they're made,
Rich
05 Feb 2016, 01:04
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skyfarer
ALTERNATE METHOD:
First you need to select students for first row which can be done in 100C50 ways
then you arrange selected 50 students in FIRST row in 50! ways
and
you arrange remaining 50 students in SECOND row in 50! ways
Total ways of arrangements = 100C50*50!*50!
I hope this helps!!!
But Just wanted to verify once more.. So I think no matter how many fragments you do of this seating arrangements, answer would always be 100! 
