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The max satisfied nine is agreed to.
The min as per me should be zero because first can be eaten by the second and second by third and third by fourth and so on... And we'll be left with one very fat yet unsatisfied piranah.. Lemme know if it is correct though..
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Bunuel
In certain pool there are 30 piranhas, which eat each other. Once a piranha eaten 3 others it's satisfied and stops eating, what are the maximum and minimum numbers of satisfied piranhas possible?

NOTE: When piranha A eats a piranha B which ate a number of piranhas previously, it's counted that A piranha still ate only one.
NOTE: Dead satisfied piranha still counts as satisfied.

This is my Q, so please comment about the quality and difficulty level.

In terms of quality it's pretty good, but two comments:
1) You need to define what the minimum number of satisfied piranhas means, because otherwise the answer is 0.
2) If you wish to simulate gmat conditions provide options (although that makes it easier, esp with min, max problems)

For Min:
Assuming the answer is not 0, I took the approach of 1 piranha eats the next 3. So the min would be 30/4 = 7 and 2 uneaten piranha. ANS = 7

For Max:
I took the approach that
P4 ate P1-3
P7 ate P6-P4
P10 ate P9-P7
Following this pattern I arrive at 9.
Although I suspect this might be incorrect :P
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The max satisfied nine is agreed to.
The min as per me should be zero because first can be eaten by the second and second by third and third by fourth and so on... And we'll be left with one very fat yet unsatisfied piranah.. Lemme know if it is correct though..

totally missed that one. Great thinkin! :-D
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yangsta8
Bunuel
In certain pool there are 30 piranhas, which eat each other. Once a piranha eaten 3 others it's satisfied and stops eating, what are the maximum and minimum numbers of satisfied piranhas possible?

NOTE: When piranha A eats a piranha B which ate a number of piranhas previously, it's counted that A piranha still ate only one.
NOTE: Dead satisfied piranha still counts as satisfied.

This is my Q, so please comment about the quality and difficulty level.

In terms of quality it's pretty good, but two comments:
1) You need to define what the minimum number of satisfied piranhas means, because otherwise the answer is 0.
2) If you wish to simulate gmat conditions provide options (although that makes it easier, esp with min, max problems)

For Min:
Assuming the answer is not 0, I took the approach of 1 piranha eats the next 3. So the min would be 30/4 = 7 and 2 uneaten piranha. ANS = 7

For Max:
I took the approach that
P4 ate P1-3
P7 ate P6-P4
P10 ate P9-P7
Following this pattern I arrive at 9.
Although I suspect this might be incorrect :P

Thank you for your response. I'll try to take into account points you brought up. As for min: I thought it was obvious, when asking about min number of satisfied fishes, that min can take 0 as well.

Answer:
MIN=0 (one fish eats second, second eats third and so on, no satisfied fish at the end)
MAX=9 (7 fishes eat 3 -->7*3+7=28, 2 left eat 6(3+3) from this seven --> 2+7=9)
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Same here.
In question like this one, min. is always 0.

Max = 9 => 4+3+3+3+3+3+3+3+3


Bunuel
yangsta8
Bunuel
In certain pool there are 30 piranhas, which eat each other. Once a piranha eaten 3 others it's satisfied and stops eating, what are the maximum and minimum numbers of satisfied piranhas possible?

NOTE: When piranha A eats a piranha B which ate a number of piranhas previously, it's counted that A piranha still ate only one.
NOTE: Dead satisfied piranha still counts as satisfied.

This is my Q, so please comment about the quality and difficulty level.

In terms of quality it's pretty good, but two comments:
1) You need to define what the minimum number of satisfied piranhas means, because otherwise the answer is 0.
2) If you wish to simulate gmat conditions provide options (although that makes it easier, esp with min, max problems)

For Min:
Assuming the answer is not 0, I took the approach of 1 piranha eats the next 3. So the min would be 30/4 = 7 and 2 uneaten piranha. ANS = 7

For Max:
I took the approach that
P4 ate P1-3
P7 ate P6-P4
P10 ate P9-P7
Following this pattern I arrive at 9.
Although I suspect this might be incorrect :P

Thank you for your response. I'll try to take into account points you brought up. As for min: I thought it was obvious, when asking about min number of satisfied fishes, that min can take 0 as well.

Answer:
MIN=0 (one fish eats second, second eats third and so on, no satisfied fish at the end)
MAX=9 (7 fishes eat 3 -->7*3+7=28, 2 left eat 6(3+3) from this seven --> 2+7=9)
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Great question Bunuel.. Keep posting
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Hi Bunuel,
MAX=3 (7 fishes eat 3 -->7*3+7=28, 2 left eat 6(3+3) from this seven --> 2+1=3)
am I correct?
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sudhanshushankerjha
Hi Bunuel,
MAX=3 (7 fishes eat 3 -->7*3+7=28, 2 left eat 6(3+3) from this seven --> 2+1=3)
am I correct?

\(MAX=9\): (7 fishes eat 3 -->7*3+7=28, 2 left eat 6(3+3) from this seven --> 2+7=9).
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good question Bunuel. I would give this a 700+ question. Thank you.
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Bunnel,

There are 30 fishes, so 10 fishes get 3 each which makes them satified so wont 10 would be the maximum # of satified piranha ? I am confused.
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Bunnel, sorry I got it :-(
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hurray! i solved it and got the right answer! I hope my logic is ok
I will write it down in a lengthy way to explain what I mean-

among 5 fishes 1 can eat
among 8 fishes 2 can eat
among 11 fishes 3 can eat
among 14 fishes 4 can eat
among 17 fishes 5 can eat
among 20 fishes 6 can eat
among 23 fishes 7 can eat
among 26 fishes 8 can eat
among 29 fishes 9 can eat

so, max 9 piranhas will be happy :)
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Bumping for review and further discussion.
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Bunuel
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Bunuel
In certain pool there are 30 piranhas, which eat each other. Once a piranha eaten 3 others it's satisfied and stops eating, what are the maximum and minimum numbers of satisfied piranhas possible?

NOTE: When piranha A eats a piranha B which ate a number of piranhas previously, it's counted that A piranha still ate only one.
NOTE: Dead satisfied piranha still counts as satisfied.

This is my Q, so please comment about the quality and difficulty level.

In terms of quality it's pretty good, but two comments:
1) You need to define what the minimum number of satisfied piranhas means, because otherwise the answer is 0.
2) If you wish to simulate gmat conditions provide options (although that makes it easier, esp with min, max problems)

For Min:
Assuming the answer is not 0, I took the approach of 1 piranha eats the next 3. So the min would be 30/4 = 7 and 2 uneaten piranha. ANS = 7

For Max:
I took the approach that
P4 ate P1-3
P7 ate P6-P4
P10 ate P9-P7
Following this pattern I arrive at 9.
Although I suspect this might be incorrect :P

Thank you for your response. I'll try to take into account points you brought up. As for min: I thought it was obvious, when asking about min number of satisfied fishes, that min can take 0 as well.

Answer:
MIN=0 (one fish eats second, second eats third and so on, no satisfied fish at the end)
MAX=9 (7 fishes eat 3 -->7*3+7=28, 2 left eat 6(3+3) from this seven --> 2+7=9)

I fell for the trap and got min as 7, but i agree totally that there could be 0 satisfied fish, while max was 9.

Good question...
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Fishes are given numbers as 1 to 30


(1 2 3) (4 5 6) (7 8 9) (10 11 12) (13 14 15) (16 17 18) (19 20 21)
------- ------- ------ ---------- ---------- ---------- ---------
(22 23 24) (25 26 27) 28
-------------------- ----------------------
29 30

Here as we see, satisfied phiranas are 22, 23, 24, 25, 26, 27, 28, 29 and 30 = 9


Bunuel
In certain pool there are 30 piranhas, which eat each other. Once a piranha eaten 3 others it's satisfied and stops eating, what are the maximum and minimum numbers of satisfied piranhas possible?

NOTE: When piranha A eats a piranha B which ate a number of piranhas previously, it's counted that A piranha still ate only one.
NOTE: Dead satisfied piranha still counts as satisfied.

This is my Q, so please comment about the quality and difficulty level.
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