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Please answer this question!  [#permalink]

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New post 05 Mar 2016, 00:00
There were two classes A and B with a total of 53 students. Students of both the classes were asked to go on a school trip but only 1/5th of the students from class A and 2/3rd of the students from class B agreed to go. What is the minimum possible number of students who did not go?

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Re: Please answer this question!  [#permalink]

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New post 05 Mar 2016, 00:22
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kalyanidon wrote:
There were two classes A and B with a total of 53 students. Students of both the classes were asked to go on a school trip but only 1/5th of the students from class A and 2/3rd of the students from class B agreed to go. What is the minimum possible number of students who did not go?


Hi,
The first step would be to find the number of possible ways to divide the students in the two classes..

INFO we have .

.
1/5 of A MEANS A should be multiple of 5.. say A= 5x
and 2/3 of B MEANS B should be multiple of 3.. say B= 3y..
so 5x+3y=53.. lets check ways x and y are integers..


1)if x=1, then 5+3y=53 or 3y =48, y= 16... Possible
the Q asks us least possible not gone, which is 4/5 th of A and 1/3 rd of B, so we should look for MIN value of A and MAX value of B..
Here in the first step itself we have got min of A, as A cannot be less than 5..
answer = 4/5 of 5 + 1/3 of 48 = 1+16=17 answer..

But incase you want to see other possiblities--
now One way is A=5 and B= 48..
Other ways will be by adding LCM of 3 and 5, 15, to A and subtracting from B..
2) A= 5+15. B=48-15 or A= 20, B=33..
3) A=20+15=35 and B= 33-15=18..
4) A=35+15=50 and B=18-15=3..

Hope it helps you


--== Message from the GMAT Club Team ==--

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This discussion does not meet community quality standards. It has been retired.


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Re: Please answer this question!   [#permalink] 05 Mar 2016, 00:22

Please answer this question!

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