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kalyanidon
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Please answer this question! 05 Mar 2016, 01:00
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There were two classes A and B with a total of 53 students. Students of both the classes were asked to go on a school trip but only 1/5th of the students from class A and 2/3rd of the students from class B agreed to go. What is the minimum possible number of students who did not go?



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kalyanidon
There were two classes A and B with a total of 53 students. Students of both the classes were asked to go on a school trip but only 1/5th of the students from class A and 2/3rd of the students from class B agreed to go. What is the minimum possible number of students who did not go?
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Hi,
The first step would be to find the number of possible ways to divide the students in the two classes..

INFO we have .

.
1/5 of A MEANS A should be multiple of 5.. say A= 5x
and 2/3 of B MEANS B should be multiple of 3.. say B= 3y..
so 5x+3y=53.. lets check ways x and y are integers..

1)if x=1, then 5+3y=53 or 3y =48, y= 16... Possible
the Q asks us least possible not gone, which is 4/5 th of A and 1/3 rd of B, so we should look for MIN value of A and MAX value of B..
Here in the first step itself we have got min of A, as A cannot be less than 5..
answer = 4/5 of 5 + 1/3 of 48 = 1+16=17 answer..

But incase you want to see other possiblities--
now One way is A=5 and B= 48..
Other ways will be by adding LCM of 3 and 5, 15, to A and subtracting from B..
2) A= 5+15. B=48-15 or A= 20, B=33..
3) A=20+15=35 and B= 33-15=18..
4) A=35+15=50 and B=18-15=3..

Hope it helps you



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