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# PnC

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Using digits 0, 1, 2, 3 how many natural numbers can be formed such t  [#permalink]

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03 Sep 2018, 01:02
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SURYA787 wrote:
Using digits 0, 1, 2, 3 how many natural numbers can
be formed such that no digit is repeated in the number?

Posted from my mobile device

Objection 1: The guidelines of posting question haven't been followed
Objection 2: Options are not available
Objection 3: Terms like Natural Numbers and Whole numbers are not used by GMAT

Solution:

There are 3 single digit (natural) positive integers numbers that can be formed using given 4 digits

There are 3*3 two digit positive integers can be formed using given digits

There are 3*3*2 three digit positive integers can be formed using given digits

There are 3*3*2*1 Four digit positive integers can be formed using given digits

Total Such numbers = 3+9+18+18 = 48

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03 Sep 2018, 01:06
SURYA787 wrote:
Using digits 0, 1, 2, 3 how many natural numbers can
be formed such that no digit is repeated in the number?

Posted from my mobile device

single digit numbers = 1,2,3 = 3 (0 is not a part of natural numbers)
two digit numbers = 3*3=9
three digit numbers = 3*3*2=18
four digit number = 3*3*2*1=18

total = 12+36=48
Re: PnC   [#permalink] 03 Sep 2018, 01:06
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# PnC

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