Bunuel
Points A = (3,9), B = (1,1), C = (5,3), and D=(a,b) lie in the first quadrant and are the vertices of quadrilateral ABCD. The quadrilateral formed by joining the midpoints of AB, BC, CD, and DA is a square. What is the sum of the coordinates of point D?
(A) 7
(B) 9
(C) 10
(D) 12
(E) 16
It can get done in a minute if you follow the logic discussed here:
https://www.gmatclub.com/forum/veritas-prep-resource-links-no-longer-available-399979.html#/2013/0 ... ry-part-i/https://www.gmatclub.com/forum/veritas-prep-resource-links-no-longer-available-399979.html#/2013/0 ... y-part-ii/Now, look at the diagram below:
Attachment:
Screenshot 2019-03-18 at 18.40.37.png
Plot the 3 co-ordinates (A, B and C) of the given quad and find their mid points to get two co-ordinates of the square (N and M). Now MP will be another side of the square such that it is perpendicular and of the same length as MN.
Hence MX = 3 = MY
NX = 1 = PY
So point P will be 3 to the right of M and 1 above M i.e. at (5, 6).
P will be the mid point of AD and hence D will be (7, 3).
Sum of the coordinates of D = 7+3 = 10
Answer (C)
I am unable to understand the below points.