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24 Oct 2013, 23:05
Kudos
Bookmarks
Hello guys,
I have a very silly question for you.
Say we have an equation, (x-2)(x+2) 0
So, x -2
or
(x-2)>0 and (x+2)2 and x<-2
So when I plot a graph it'd look like this
(attaching the image)
now what
What's the solution if I go this way of plotting a graph?
What is the solution at all? since no area of the numberline actually intersects??
its a very lengthy and confusing process.
I need to get my basics right about inequalities problems.
can someone give me links to inequalities concepts?
thanks,
infymys
I have a very silly question for you.
Say we have an equation, (x-2)(x+2) 0
So, x -2
or
(x-2)>0 and (x+2)2 and x<-2
So when I plot a graph it'd look like this
(attaching the image)
now what
What's the solution if I go this way of plotting a graph?
What is the solution at all? since no area of the numberline actually intersects??
its a very lengthy and confusing process.
I need to get my basics right about inequalities problems.
can someone give me links to inequalities concepts?
thanks,
infymys
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
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25 Oct 2013, 02:32
Kudos
Bookmarks
Hi,
You may read through these post for better understanding of inequalities.
1.https://gmatclub.com/forum/inequalities-basics-154285.html
2. https://gmatclub.com/forum/graphic-approach-to-problems-with-inequalities-68037.html
3. https://gmatclub.com/forum/inequations-inequalities-part-154664.html
4.https://gmatclub.com/forum/inequations-inequalities-part-154738.html
5. https://gmatclub.com/forum/tips-and-tricks-inequalities-150873.html
6.https://gmatclub.com/forum/quick-way-to-graph-inequalities-76255.html
And plenty of them still in the forum, Use the tag search for browsing the theories.. Also please use the right forum to post the questions.
Moderators. Please move this post right forum
You may read through these post for better understanding of inequalities.
1.https://gmatclub.com/forum/inequalities-basics-154285.html
2. https://gmatclub.com/forum/graphic-approach-to-problems-with-inequalities-68037.html
3. https://gmatclub.com/forum/inequations-inequalities-part-154664.html
4.https://gmatclub.com/forum/inequations-inequalities-part-154738.html
5. https://gmatclub.com/forum/tips-and-tricks-inequalities-150873.html
6.https://gmatclub.com/forum/quick-way-to-graph-inequalities-76255.html
And plenty of them still in the forum, Use the tag search for browsing the theories.. Also please use the right forum to post the questions.
Moderators. Please move this post right forum
26 Oct 2013, 13:31
Kudos
Bookmarks
Hi Infymys,
Your approach to solve this question is right and you have reached to the solution.
The answer to this problem is:
either (x -2), say R1 or (x>2 and x<-2), say R2.
If we consider only integer values, then
R1 = {-1, 0, 1} &
R2 = {..., -5, -4, -3, 3, 4, 5, ...}
x can be any one of these numbers.
So, possible values of x are {..., -5, -4, -3, -1, 0, 1, 3, 4, 5, ...}
For this problem, you can not find a single value of x. The value of x lies in a range.
If you will pick any value in this range, it will satisfy the equation (x - 2)(x + 2) < 0
For example, let x=1, then (x - 2)(x + 2) = (1 - 2)(1 + 2) = (-1)(3) = -3 (which is less than 0).
For a value, which is not there in the range, (in this case, -2 & 2), it will not satisfy the equation.
When x=-2, (x - 2)(x + 2) = (-2 - 2)(-2 + 2) = (-4)(0) = 0 (does not satisfy the equation).
Your approach to solve this question is right and you have reached to the solution.
The answer to this problem is:
either (x -2), say R1 or (x>2 and x<-2), say R2.
If we consider only integer values, then
R1 = {-1, 0, 1} &
R2 = {..., -5, -4, -3, 3, 4, 5, ...}
x can be any one of these numbers.
So, possible values of x are {..., -5, -4, -3, -1, 0, 1, 3, 4, 5, ...}
For this problem, you can not find a single value of x. The value of x lies in a range.
If you will pick any value in this range, it will satisfy the equation (x - 2)(x + 2) < 0
For example, let x=1, then (x - 2)(x + 2) = (1 - 2)(1 + 2) = (-1)(3) = -3 (which is less than 0).
For a value, which is not there in the range, (in this case, -2 & 2), it will not satisfy the equation.
When x=-2, (x - 2)(x + 2) = (-2 - 2)(-2 + 2) = (-4)(0) = 0 (does not satisfy the equation).
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
