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15 Jul 2017, 21:54
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
57% (01:30) correct
43%
(01:19)
wrong
based on 87
sessions
History
Date
Time
Result
Not Attempted Yet
If a and b are integers and a*b=2, is a>b?
(1) \(\frac{a}{b}>1\)
(2) \(a^2>b^2\)
self made
(1) \(\frac{a}{b}>1\)
(2) \(a^2>b^2\)
self made
Pure algebraic questions like this one are no longer part of the GMAT Data Sufficiency syllabus.
For relevant Data Sufficiency questions, please check the Data Sufficiency forum:
Data Sufficiency Forum
Data Sufficiency Forum
16 Jul 2017, 00:18
Kudos
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IMO the answer is
Stem : a and b and integers and their product is 2. Possible values of a,b = (2,1) or (1,2) or (-2,-1) or (-1, -2)
Needed: Is a > b?
I found it easier to keep track of the possibilities by using a table and Working through S1, S2 and S1+S2. Table is attached.
From the Table we can see
S1 : a and b could be (2,1) or (-2,-1). So a > b or a < b. Insuff
S2: \(a^2 > b^2 => a^2-b^2 > 0\).
a and b could be (2,1) or (-2,-1). So a > b or a < b. Insuff
S1+S2: a and b could still be (2,1) or (-2,-1). So a > b or a < b. Insuff
Even with both statements its not suff.
I hope I am correct
E.
Stem : a and b and integers and their product is 2. Possible values of a,b = (2,1) or (1,2) or (-2,-1) or (-1, -2)
Needed: Is a > b?
I found it easier to keep track of the possibilities by using a table and Working through S1, S2 and S1+S2. Table is attached.
From the Table we can see
S1 : a and b could be (2,1) or (-2,-1). So a > b or a < b. Insuff
S2: \(a^2 > b^2 => a^2-b^2 > 0\).
a and b could be (2,1) or (-2,-1). So a > b or a < b. Insuff
S1+S2: a and b could still be (2,1) or (-2,-1). So a > b or a < b. Insuff
Even with both statements its not suff.
I hope I am correct
Attachments
Quant question by Chetan2u.png [ 14.8 KiB | Viewed 2346 times ]
14 Aug 2017, 03:52
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chetan2u
By using numbers we can arrive at E but I have a doubt in using algebra.
Since a*b=2, both a and b has to be same sign.
St.1: \(\frac{a}{b}>1\)
If a and b are positive, we can conclude a>b.
If a and b are negative, \(\frac{-a}{-b}\), will those signs not cancel out and become just a/b ? Should we invert > sign even when we cancel sign in numerator and denominator?
Please advise.
