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22 Feb 2018, 21:07
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C
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In the figure above, all streets run in straight lines. If the angle of intersection of Avenue Foche and Victor Hugo Street is 90° and Avenue Foche is parallel to St. Michael's Boulevard, then what is the area of the shaded portion of the figure (expressed in square feet)?
(A) 600
(B) 750
(C) 1350
(D) 2400
(E) 3750
Attachment:
2018-02-23_0806.png [ 58.37 KiB | Viewed 2033 times ]
22 Feb 2018, 21:25
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Attachment:
2018-02-23_0806.png [ 56.54 KiB | Viewed 1799 times ]
Area of the shaded region is the sum of the area of the rectangle and the area of the right-angled triangle
Area of rectangle = \(20*30 = 600\)
Area of triangle = \(\frac{1}{2}*50*30 = 25*30 = 750\)
Therefore, the area of the shaded region is \(600 + 750 = 1350\)(Option C)
22 Feb 2018, 23:50
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We can split the image into 2 areas, one rectangle and one triangle.
Area of rectangle = 30 * 20 = 600
Are of triangle= (50*30)/2 = 750
Adding both = 1350
Ans: C
Area of rectangle = 30 * 20 = 600
Are of triangle= (50*30)/2 = 750
Adding both = 1350
Ans: C
