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09 Sep 2018, 08:03
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
43% (01:53) correct
57%
(02:03)
wrong
based on 63
sessions
History
Date
Time
Result
Not Attempted Yet
What is the value of b?
(1) The radius of the circle is 6.
(2) ac = 12
Attachment:
image009.jpg [ 4.47 KiB | Viewed 2248 times ]
Pure algebraic questions like this one are no longer part of the GMAT Data Sufficiency syllabus.
For relevant Data Sufficiency questions, please check the Data Sufficiency forum:
Data Sufficiency Forum
Data Sufficiency Forum
10 Sep 2018, 12:47
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PQ=a^2+b^2
QR=b^2+c^2
Because PQR is a right angled triangle, we have PQ^2+QR^2=PR^2.
(a^2+b^2)+(b^2+c^2)=(a+c)^2
(a^2+2*b^2+c^2)=a^2+c^2+2ac
2b^2=2ac
b^2=ac
b=sq.root of ac=sq.root of 12.
Hi Bunuel, shouldn't the answer be B?
QR=b^2+c^2
Because PQR is a right angled triangle, we have PQ^2+QR^2=PR^2.
(a^2+b^2)+(b^2+c^2)=(a+c)^2
(a^2+2*b^2+c^2)=a^2+c^2+2ac
2b^2=2ac
b^2=ac
b=sq.root of ac=sq.root of 12.
Hi Bunuel, shouldn't the answer be B?
23 Sep 2018, 15:33
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Hi rajudantuluri,
It is not mentioned anywhere that PR is the diameter of the circle, so you can not assume that PQR is a right angled triangle.
The answer is E.
It is not mentioned anywhere that PR is the diameter of the circle, so you can not assume that PQR is a right angled triangle.
The answer is E.
23 Sep 2018, 19:28
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richa2909
the two point P and R lies on the surface of the circle and the line PR passes through the radius then PR should be the diameter (in my opinion).
Take perpendicular bisector as T in the diagram. Take angle PRQ as X. Since triangle PQT is similar to triangle PQR.
b/c=(a+c)/b..
i.e., b^2=c(a+c).
the answer choice 1)provide a+C=12. but the value of c or a cannot be found .so , it is insufficient
2)ac=12 but the value of c or a cannot be found .so , it is insufficient.
combining two equation also does not provide solution. so answer is E
