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13 Oct 2018, 10:29
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
32% (02:24) correct
68%
(02:11)
wrong
based on 60
sessions
History
Date
Time
Result
Not Attempted Yet
There is a circular garden of Diameter = r. Three points are chosen independently and at random on the boundary of the Garden. What is the approximate probability that none of the three points lies more than a straight-line distance of r/2 away from any other of the three points?
(A) 1/9
(B) 1/12
(C) 1/18
(D) 1/24
(E) 1/27
(A) 1/9
(B) 1/12
(C) 1/18
(D) 1/24
(E) 1/27
Weekly Quant Quiz #4 Ques 7
13 Oct 2018, 11:28
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P(P1) =1 .....as can be placed anywhere in the circle. .......................... ref pic 01
p(P2)= 120/360=1/3 as........ p2 can be at max r(radius) dist from p1. thus forms equilateral trangle at both sides when reference OP1. Thus max possible placement is at 1/3 of 360 deg
..............ref pic 02
For P3 only 2 cases:
case 01 : p1 & p2 at same pt thus p3 at r dist , hence fracton again covers 120 deg out of 360 . Hence p3= 120/360=1/3 ...........ref pic 03
case 02 : when p1 & p2 are not at the same point , then the max arc covered by 2 max distant points is 60. p3=60/360 =1/6 ................ref pic 04
P(P1 P2 P3case01)= 1*1/3*1/3 =1/9
P(P1 P2 P3case01)= 1*1/3*1/6 =1/18........ as these are the 2 extreme cases the actual P is in between.
..................Thus Ans is B.
p(P2)= 120/360=1/3 as........ p2 can be at max r(radius) dist from p1. thus forms equilateral trangle at both sides when reference OP1. Thus max possible placement is at 1/3 of 360 deg
..............ref pic 02
For P3 only 2 cases:
case 01 : p1 & p2 at same pt thus p3 at r dist , hence fracton again covers 120 deg out of 360 . Hence p3= 120/360=1/3 ...........ref pic 03
case 02 : when p1 & p2 are not at the same point , then the max arc covered by 2 max distant points is 60. p3=60/360 =1/6 ................ref pic 04
P(P1 P2 P3case01)= 1*1/3*1/3 =1/9
P(P1 P2 P3case01)= 1*1/3*1/6 =1/18........ as these are the 2 extreme cases the actual P is in between.
..................Thus Ans is B.
Attachments
20181013_145432.jpg [ 943.56 KiB | Viewed 2543 times ]
General Discussion
13 Oct 2018, 10:39
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According to me option (C) is correct. Please find the solution.
Regards,
GLadi
Regards,
GLadi
Attachments
Q4_7.jpeg [ 94 KiB | Viewed 2571 times ]
