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11 Feb 2019, 02:25
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D
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96% (01:43) correct
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In the preceding figure, square ABCD has sides the length of 4 units, and M and N are the midpoints of AB and CD, respectively. What is the perimeter, in units, of AMCN?
(A) 6
(B) \(6 \sqrt{5}\)
(C) \(2 +2 \sqrt{3}\)
(D) \(4 +4 \sqrt{5}\)
(E) \(8 \sqrt{5}\)
Attachment:
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KanishkM
Joined: 09 Mar 2018
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Schools: DeGroote'21 Desautels '21 NUS '21
11 Feb 2019, 02:32
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Bunuel
IMO D
So 2 sides of AMNC will be 2, since M and N are midpoints
AN = \(\sqrt{20}\), which will be equal to MC as well
Perimeter = 4 + 2* 2 \(\sqrt{5}\)
\(4 +4 \sqrt{5}\)
eswarchethu135
11 Feb 2019, 02:48
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Attachment:
image1.jpg [ 24.29 KiB | Viewed 2069 times ]
From the above fig, the perimeter of AMCN is
\(2 + 2 + \sqrt{20} + \sqrt{20}\)
\(4 + 2\sqrt{5} + 2\sqrt{5}\)
\(4 + 4\sqrt{5}\)
OPTION: D
