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Updated on: 22 Jul 2019, 06:14
Originally posted by Bunuel on 02 Apr 2019, 23:43.
Last edited by Sajjad1994 on 22 Jul 2019, 06:14, edited 1 time in total.
Last edited by Sajjad1994 on 22 Jul 2019, 06:14, edited 1 time in total.
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Difficulty:
55%
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Question Stats:
68% (02:50) correct
32%
(02:35)
wrong
based on 79
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In the figure, if AB = 10, what is the length of the side CD ?
A. \(5\)
B. \(5 \sqrt{3}\)
C. \(\frac{10}{\sqrt{3}}\)
D. \(10\)
E. \(10 \sqrt{3}\)
Source: Nova GMAT
Difficulty Level: 650
Difficulty Level: 650
Attachment:
#GREpracticequestion In the figure, if AB = 10.jpg [ 19.65 KiB | Viewed 6440 times ]
aniket16c
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03 Apr 2019, 21:40
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m(BAC) = invsin(5/10) = 30 deg
m(EDC) = 60 deg
tan(60) = EC/CD
CD= 10/sqrt(3)
m(EDC) = 60 deg
tan(60) = EC/CD
CD= 10/sqrt(3)
firas92
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04 Apr 2019, 00:29
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Triangles ABC & CDE are similar since they have same angles.
Triangle ABC is in 1-√3-2 ratio so CDE must also have the same ratio
So CD/EC=1/√3 => CD=EC/√3 = 10/√3
Triangle ABC is in 1-√3-2 ratio so CDE must also have the same ratio
So CD/EC=1/√3 => CD=EC/√3 = 10/√3
