The figure shows the intersection of a Square ABCD and a Circle. What

Question

GMATBusters’ Quant Quiz Question -2 https://gmatclub.com/forum/download/file.php?id=51956 The figure shows the intersection of a Square ABCD and a Circle. What is the Perimeter of the Square ABCD? 1) X = 1 2) AC and BD are perpendicular to each other 123.JPG

aqua1 · Answer

Answer :E

I'm assuming in the given diagram the diameter passes through the intersection of the diagonals:

a= side of the square
d=diameter of the circle
Requirement is to find 4a ?
= 4(d-x)

1) x=1
for x=1 perimeters =4(d-1)
multiple answers as d changes hence insufficient.

2) This basically gives product information. In a square diagonal are perpendicular. Not sufficient.

Aviral1995 · Answer

Here lets start by considering radius of circle as r. Let O be the center of circle and let M be the midpoint of side BC where Perpendicular from O meets BC.
By applying right angle property
 (OB)^2 = (BM)^2 + (OM)^2
r^2 = (BM)^2 + (r-x)^2
on solving, we get (BM)^2 = x(2r-x)

since from 1 we know the value of x, we get value of (BM)^2 as 2r-1

so we cannot find the perimeter of square just from 1

(2) since its told that abcd is a square, we can already infer what is given in 2

Taking both 1 and 2, still we donot have enough information to find the value of r so answer is E

numb007 · Answer

Ans: A
(1): from the mid point of the circle O draw radius to point B and C .Since the triangle OBC is an isosceles triangle with angle BOC = 90 degree. We can say sin 45 = OB/OX. 
OX=radius-1
OB=radius.
Now we can find radius and hence the perimeter.
(2). This is a redundant info . Its given that the figure is square which implies that diagonals will intersect at 90 degree.

Archit3110 · Answer

#1
X=1 ;
insufficient as we dont know the center of circle also X=1 is the highest point of circle from square 
#2
AC and BD are perpendicular to each other
the lines will intersect at center at 90* , but center of circle is not clear ; insufficient 
from 1 &2
we can determine the sides of the digonals using 45:45:90 ; but will have unknow value of distance from center to circle side X=1
radius ; a+1 ; side of square ; 2a and perimeter ; 8a ; but value of a is not know 
insufficient
IMO E

The figure shows the intersection of a Square ABCD and a Circle. What is the Perimeter of the Square ABCD?
1) X = 1
2) AC and BD are perpendicular to each other

vasuca10 · Answer

Let us look at each statements one by one

1) X = 1
This statement does not provides us any information which will provide us the dimensions of the square, we cannot arrive at any side dimension length of the square hence statement 1 alone is not sufficient

2) AC and BD are perpendicular to each other

This statement does not provides us any information which will provide us the dimensions of the square, hence statement 1 alone is not sufficient

Even when we combine information in both the statements together, it won't give us any information about square dimensions or of the circle, hence both statements together are also not sufficient.
Answer is Option E, even both the statements together are also not sufficient.

Raxit85 · Answer

The figure shows the intersection of a Square ABCD and a Circle. What is the Perimeter of the Square ABCD?

Tricky one for me, still i'll try.

1) X = 1, 
Insufficient as we can't find the radius of the circle, which can give us diameter of the circle, which in turn could help to find side or diagonal of square.

2) AC and BD are perpendicular to each other
It implies that diagonals pass through the center of the circle. But still we can't find the radius/diameter of the circle/diagonal of the square/side of square. Hence insufficient.

1) + 2) 
Square is inscribed from the circle as AC and BD are perpendicular to each other. Still can not find the side of square. Hence insufficient.

Imo. E

gravito123 · Answer

The answer is E.

EXPLANATION:

Please refer to the attached figure:
We have assumed a radius is drawn from B and C, meeting at the point which is coolinear to the point x distance is separated from the square. Hence, if the total distance is R, the point till the square edge (where x distance is separated from the circle), is r - x.

We can see, perimeter is:
r + k + 2l + r + k + 2l.

Also, we know,   l = \sqrt{r^2 - (r-1)^2 }  
Hence, L equals,   \sqrt{2r - 1 }

Hence, solving the equation, we get perimeter as function of R as: 
  4r - 2 + 4\sqrt{2r-1}

Since the value of R can vary, the perimeter can vary and have more than one answer.
Hence, E is the answer.

jhavyom · Answer

In the above figure, let OB = OC = R. Let, OE = y, AB = 2a
Now, R = x + y ...(i)
R + y = 2a ...(ii)
In triangle OEB, R^2 = y^2 + a^2 ...(iii)

Substituting (i) in (iii), we get
(x+y)^2 = y^2 + a^2
 x^2 + 2xy + y^2 = y^2 + a^2
 x^2 + 2xy = a^2 ...(iv)

Substituting (i) in (ii), we get
x+2y = 2a

Multiplying above equation by x, we get

x^2 + 2xy = 2ax ... (v)

From (iv) and (v), we get

a^2 = 2ax

a=0 or a=2x

Since, a is a length, it can not be non - positive.

Therefore, a = 2x ... (vi)

(1) x = 1
 Substituting in (vi), we get
 a = 2. Therefore, perimeter = 8a = 16.
 Clearly, statement 1 is sufficient.

(2) AC and BD are perpendicular to each other
 Since, ABCD is a square AC and BD are perpendicular to each other. We do not get any information about the length of the square.
 Therefore statement 2 is insufficient.

Choice A is the answer.

GCMEMBER · Answer

For every square and circle which exist as shown in the figure, distance x will be unique and no two combination of square and circle can have same value of x.

(1) For x=1, we have a unique figure and thus the perimeter of the square can be determined.
Therefore, statement 1 is sufficient.

(2) AC and BD are perpendicular to each other
ABCD is a square AC and BD are always perpendicular to each other.
Not sufficient.

A is the answer.

saiprasanna · Answer

jhavyom  can you explain how R+Y =2a in your explanation

GMATBusters · Answer

The solution of this question is as per the sketch: https://gmatclub.com/forum/download/file.php?id=52412 WhatsApp Image 2020-01-06 at 1.29.51 PM.jpeg

GMATBusters · Answer

As per the jhyavyom solution, Side of the square is taken as 2a
Hence R+2a = side of the square = 2a

I hope it is clear, feel free to tag me in case of any doubt.

Happy Learning

draftpunk · Answer

Please expand on: R + y = 2a

How can that be true if R^2 = a^2 + y^2?

gmatbusters   jhavyom

sudhirgmat1 · Answer

GMATBusters 
sorry for this but couldn`t understand how E lie on the diameter of the circle

GMATBusters · Answer

By symmetry, it lies on diameter. It can be proved but better to use the principle of symmetry in GMAT. 
Also, since the dimensioning line has 2 arrows, it means the max distance between the circle and circle, which is when E lies on diameter (otherwise the exact point on circle must have been specified).

uc26 · Answer

Hi  GMATBusters ,

I had a doubt regarding the symmetry used here. We need to assume that the figure drawn is symmetrical?
Because based on that assumption, we get that EC and EB are S/2 and E lies on the diameter of the circle. I didn't make the assumption and ended up choosing E.
In what situations do we need to assume that the figure given is symmetrical?

Thanks and Regards,
Udit

bumpbot · Answer

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The figure shows the intersection of a Square ABCD and a Circle. What

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