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Updated on: 30 Jan 2020, 21:31
Originally posted by GMATBusters on 30 Jan 2020, 12:04.
Last edited by GMATBusters on 30 Jan 2020, 21:31, edited 1 time in total.
Last edited by GMATBusters on 30 Jan 2020, 21:31, edited 1 time in total.
typo removed
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
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Question Stats:
76% (01:41) correct
24%
(01:58)
wrong
based on 29
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Inside a square plot of side 28m, a circular garden is developed which exactly fits in the square plot. What is the area of the space left out in the square plot after developing the garden?
A) 98 m 2
B) 146 m 2
C) 84 m 2
D) 168 m 2
E) None of these
A) 98 m 2
B) 146 m 2
C) 84 m 2
D) 168 m 2
E) None of these
30 Jan 2020, 12:23
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gmatbusters
Ther is missing information in the question. DImension of square or radius of garden is unavailable.
Space left out = Area of Square - Area of Circular garden
30 Jan 2020, 20:16
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Square Area: 28x28 =784
Dia of circle = 28 (side of square), So r=14
Area of circle = πr^2 = (22/7)x14x14 = 22x2x14 = 22x28 = 616
Left out area: 784-616 = 168 m^2
IMO-D
Dia of circle = 28 (side of square), So r=14
Area of circle = πr^2 = (22/7)x14x14 = 22x2x14 = 22x28 = 616
Left out area: 784-616 = 168 m^2
IMO-D
