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01 Feb 2020, 19:29
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
42% (02:41) correct
58%
(02:55)
wrong
based on 92
sessions
History
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Not Attempted Yet
GMATBusters’ Quant Quiz Question -5
For questions from previous quizzes click here
In the figure above, QX = 10 and PQ = 6, what is the length of QY?
1) Angle QPY = 90 deg
2) Length of XZ = 100/6
Attachment:
Q.JPG [ 29.54 KiB | Viewed 7665 times ]
01 Feb 2020, 19:32
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The Official Solution is as follows:
WhatsApp Image 2020-02-03 at 6.49.55 PM (4).jpeg [ 75.87 KiB | Viewed 7513 times ]
Attachment:
WhatsApp Image 2020-02-03 at 6.49.55 PM (4).jpeg [ 75.87 KiB | Viewed 7513 times ]
01 Feb 2020, 20:54
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1) Since Angle QPY = 90 deg, by the Pythagorean theorem, PX=sqr(10^2-6^2)=8. We also know that the altitude of the right triangle XYQ, PQ, can be calculated with the following formula: PQ^2=PY*PX. From here we can calculate PY since we already know the values of PQ and PX. Likewise, QY can also be determined by using the Pythagorean theorem in the right triangle PQY as the values of PQ and PY are known.
Clearly, this statement is sufficient.
2) Using the Pythagorean theorem, we can determine the value of QZ in the right triangle XQZ. Then, based on the same logic as explained in the case above, the altitude of right triangle XYZ, XQ, follows the formula: XQ^2=QZ*YQ. From here YQ can be also calculated.
Clearly, this statement is sufficient.
Answer: D
Clearly, this statement is sufficient.
2) Using the Pythagorean theorem, we can determine the value of QZ in the right triangle XQZ. Then, based on the same logic as explained in the case above, the altitude of right triangle XYZ, XQ, follows the formula: XQ^2=QZ*YQ. From here YQ can be also calculated.
Clearly, this statement is sufficient.
Answer: D
