Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 2211:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment- Nov 23
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. 
Nov 2510:00 AM EST
-11:00 AM EST
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
01 Feb 2020, 19:29
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
42% (02:41) correct
58%
(02:55)
wrong
based on 92
sessions
History
Date
Time
Result
Not Attempted Yet
GMATBusters’ Quant Quiz Question -5
For questions from previous quizzes click here
In the figure above, QX = 10 and PQ = 6, what is the length of QY?
1) Angle QPY = 90 deg
2) Length of XZ = 100/6
Attachment:
Q.JPG [ 29.54 KiB | Viewed 7492 times ]
01 Feb 2020, 19:32
Kudos
Bookmarks
The Official Solution is as follows:
WhatsApp Image 2020-02-03 at 6.49.55 PM (4).jpeg [ 75.87 KiB | Viewed 7319 times ]
Attachment:
WhatsApp Image 2020-02-03 at 6.49.55 PM (4).jpeg [ 75.87 KiB | Viewed 7319 times ]
01 Feb 2020, 20:54
Kudos
Bookmarks
1) Since Angle QPY = 90 deg, by the Pythagorean theorem, PX=sqr(10^2-6^2)=8. We also know that the altitude of the right triangle XYQ, PQ, can be calculated with the following formula: PQ^2=PY*PX. From here we can calculate PY since we already know the values of PQ and PX. Likewise, QY can also be determined by using the Pythagorean theorem in the right triangle PQY as the values of PQ and PY are known.
Clearly, this statement is sufficient.
2) Using the Pythagorean theorem, we can determine the value of QZ in the right triangle XQZ. Then, based on the same logic as explained in the case above, the altitude of right triangle XYZ, XQ, follows the formula: XQ^2=QZ*YQ. From here YQ can be also calculated.
Clearly, this statement is sufficient.
Answer: D
Clearly, this statement is sufficient.
2) Using the Pythagorean theorem, we can determine the value of QZ in the right triangle XQZ. Then, based on the same logic as explained in the case above, the altitude of right triangle XYZ, XQ, follows the formula: XQ^2=QZ*YQ. From here YQ can be also calculated.
Clearly, this statement is sufficient.
Answer: D
