https://e-gmat.com/blogs/wp-content/uploads/2015/04/hero-img-e1430404594612.png 3 deadly mistakes you must avoid in LCM- GCD questions Before you start reading this article, ask yourselves the following question: a) Are you among those who wish that they do not encounter a LCM-GCD question on their exam day or b) Are you among those who take a guess whenever they come across a LCM-GCD question or c) Are you among those who try their mighty hard but still fall short of the correct answer in a LCM-GCD question If yes , this article was waiting for you the moment you thought of taking the GMAT. We at e-GMAT believe in making GMAT ‘easy’ for you. This piece of article is one among the many in that direction. Based on our extensive student interaction for more than 1000+ students spread over the live sessions, forum queries and our recently conducted The E-GMAT Number Properties Knockout that was attempted more than 5000 times, we have identified these three primary pitfalls in the concepts of LCM-GCD: 1. Getting confused by different names of LCM & GCD 2. Not having prime factorization as the default approach 3. Being unmindful of constraints on LCM & GCD In this article, we will explain the pitfalls in LCM-GCD questions along with the measures to overcome these pitfalls to help you ace 700+ questions of the topic. Let’s begin with the first and the most common pitfall. 1. Getting confused by different names of LCM and GCD LCM-GCD are defined in various terms and phrases in questions which appear in GMAT. If you are not able to decipher the hidden meaning behind these terms you are likely to waste your precious time and even worse may approach the question with a disastrous approach. Thus, it is of utmost importance to know when the question is talking about LCM-GCD. Let’s see the ways in which a question can encrypt the message of LCM-GCD. GCD can be expressed as the following terms/phrases: https://e-gmat.com/blogs/wp-content/uploads/2015/04/GCD-Pitfall-1-e1430404146535.jpg a) x is the GCD of 12 & 18 b) x is the HCF of 12 & 18 (HCF stands for Highest Common Factor) c) x is the highest number which divides both 12 & 18 All the 3 terms above refer to the GCD of 12 & 18 i.e. 6. Try focusing on keywords such as ‘Highest’, ‘Greatest’ . These words are an indication of the question talking about the GCD of a set of numbers in a LCM-GCD question. Let’s see now the terms/phrases which are used to express LCM: https://e-gmat.com/blogs/wp-content/uploads/2015/04/LCM-Pitfall-1-e1430403946691.jpg a) z is the LCM of 12 & 18 b) z is the lowest number which is divisible by both 12 & 18 c) z is the lowest number which has 12 & 18 as its factors All the above terms refer to the LCM of 12 & 18 i.e. 36. Try focusing on keyword ‘lowest’ which can be an indication of question talking about LCM of a set of numbers. The important point to remember for identification of both LCM & GCD is the definition of these terms. While GCD is the factor/divisor of a set of numbers, LCM is the multiple of a set of numbers . Whenever you are presented with a phrase which confuses you between LCM-GCD, try to breakdown the statement in the terms of factors and multiples. For example, refer the following question: Q1: Two positive integers a and b are divisible by 5, which is their largest common factor. What is the value of a and b? I. The lowest number that has both integers a and b as its factors is the product of one of the integers and the greatest common divisor of the two integers. II. The smaller integer is divisible by 4 numbers and has the smallest odd prime number as its factor. The question plays with words when talking about LCM-GCD. Try answering this question by deciphering the message of LCM-GCD hidden in it. You can access the detailed solution here . TAKEAWAY I. LCM of a set of numbers is divisible by all the numbers in the set II. GCD of a set of numbers divides all the numbers in the set Keeping these two definitions in mind and your heart will always keep you in good stead whenever you face a LCM-GCD question. 2. Not having prime factorization as the default approach Many of the students at some time or the other have avoided doing prime factorization of a set of numbers for finding their LCM & GCD. Such an approach towards a LCM-GCD question most often leads to incorrect solution costing you precious marks and time We will explain you here, why and how prime factorization is a robust method in LCM-GCD questions and the potential pitfalls which you may avoid on your journey to a perfect quant score https://e-gmat.com/blogs/wp-content/uploads/2015/04/Prime-Factorization-e1430404785545.jpg Let’s look at the following official question: Q2: If n is a positive integer, is n a multiple of 24? I. n is a multiple of 4 II. n is a multiple of 6 The most common fallacy committed by students in such a question is to express n as a multiple of 4 & 6 i.e. 4x and 6y respectively and write n = 24xy. With this they conclude that n is a multiple of 24 which is an incorrect analysis. Students who get it right are the ones who prime factorize 4 & 6 and find that I. n is a multiple of 2^2 - so, n is a number of the form 2^2*k II. n is a multiple of 2*3 - so, n is a number of the form 2*3m The key here is to observe that n can be expressed as a multiple of maximum of 2^2 and as a multiple of maximum of 3^1 . Combining these two, we can say that n can be expressed as a multiple of 2^2 * 3 i.e. 12 . Hence n is a multiple of 12 and not 24 . Thus it can be seen that the method of prime factorization helps in eliminating such mistakes in the approach of the students. The other and the most significant benefit of prime factorization is to help you remember an easy mnemonic for calculating LCM & GCD. For calculating the GCD (Greatest Common Divisor), use the lowest power of primes of the set of numbers and for calculating the LCM (Least Common Multiple) use highest power of primes of the set of numbers . It’s a golden approach where you are never going to commit an error while calculating LCM-GCD of a set of numbers. Also, this approach is particularly helpful when calculating LCM-GCD of more than 2 numbers where the division method usually fails or takes up a lot of time. Let’s understand another advantage of using prime factorization in LCM-GCD question with an example: Q3: If the LCM of 36 & x is 72, what are the possible values of x? At the first look, the question seems to have insufficient information provided. Let’s see if the prime factorization method leads to an answer. It’s given that 72 is the LCM of 36 & x. Prime factorizing 72 would give us 72 = 2^3 * 3^2 Similarly 36 can be prime factorized as 36 = 2^2 * 3^2 . Now, we know that for calculating LCM we take the highest power of primes. Since 72 has 3^2 in it x can have either { 3^0,, 3^1 , 3^2 }. Similarly x will have 2^3 in it as 36 has only 2^2 in it and the LCM has 2^3 in it. Now, x can’t have any more prime factor other than 2 or 3 as the LCM does not have any other prime factor apart from 2 and 3. So, possible values of x = { 2^3 * 3^0, 2^3 * 3^1, 2^3 * 3^2 } = { 8, 24, 72 }. Thus, you see that prime factorization leads you out of a situation where the information seemed insufficient at the very first instant. TAKEAWAY I. Use Prime Factorization as your first line of offense against LCM-GCD questions https://e-gmat.com/blogs/wp-content/uploads/2018/07/FT-header3-e1532524244114.jpg 3. Being unmindful of constraints on LCM & GCD A few questions on GMAT test your understanding of the possible values of LCM & GCD of a set of integers. For example, have a look at the following official question( OG13 QR2, Problem Solving QNo: 98): Q4: Which of the following CANNOT be the greatest common divisor of two positive integers x and y? (A) 1 (B) x (C) y (D) x -y (E) x + y The above question directly tests your knowledge of the range of LCM & GCD. Students not aware of the range of GCD would have trouble solving this question in the given time frame. The solution to this question can be accessed here . Let’s see & observe how we can find the range of LCM & GCD and how it can be used for solving questions on LCM-GCD. GCD As we know, GCD of a set of integers is the factor of all the integers in the set. Now, factor of an integer can’t be greater than the magnitude of the integer itself. Thus, the GCD of a set of integers can’t be greater than the magnitude of the smallest integer of the set. GCD of a set of integers 1 From the above two analysis we can conclude that 1 < = GCD of a set of integers < = Magnitude of the smallest integer of the set Let’s see the range of LCM now. LCM As we know, LCM of a set of integers is the multiple of all the integers in the set. Now, the multiple of an integer can’t be smaller than the magnitude of the integer itself. Hence, common multiple of a set of integers can’t be smaller than the magnitude of the largest integer of the set. LCM of a set of integers => Magnitude of the largest integer of the set For finding the upper range of LCM of a set of integers let’s assume two integers P = a^x * b^y and Q = c^z where a, b, c are three distinct prime numbers. As we know that for calculating LCM we take the highest powers of the prime numbers, so LCM (P, Q) = a^x * b^y * c^z = P * Q. LCM of a set of integers <= Product of magnitude of all integers in the set From the above two analysis we can conclude that, Magnitude of the largest integer of the set <= LCM of a set of integers<= Product of magnitude of all integers in the set https://e-gmat.com/blogs/wp-content/uploads/2015/04/LCM-GCD-Range-e1430404443502.jpg From the above interpretation and knowing that Product of all integers in the set = GCD * LCM , we can say that when LCM is equal to the product of all integers in the set, GCD = 1. We also remember that GCD = 1 when the integers of a set do not have any common prime factor. Thus we can say that for a set of integers which don’t have a common prime factor, GCD = 1 and LCM = Product of all integers on the set. Given below are some practice questions which test your concepts of LCM-GCD Q5: If A and B are positive integers greater than 1 such that the GCD of A and B is 1, then which of the following must be true? I. A and B are prime numbers. II. A and B are consecutive numbers. III. A and B do not have a common prime factor IV. The product AB has two prime factors V. A and B have the opposite even-odd nature (A) I and II only (B) III only (C) I, V only (D) I,II, III, V only (E) I, II, III, IV, V The solution of the question can be accessed here Q6: For two positive integers A & B, what is the highest number that divides completely the product of integers from 1 to A and 1 to B such that B = A + 29. (A) 1 (B) Product of all integers from 1 to A (C) Product of all integers from 1 to B (D) 29*A (E) Can’t be determined The solution of the question can be accessed here TAKEAWAY I. 1 < = GCD of a set of integers < = Magnitude of the smallest integer of the set II. Magnitude of the largest integer of the set <= LCM of a set of integers<= Product of magnitude of all integers in the set https://e-gmat.com/blogs/wp-content/uploads/2018/07/FT-GC-FB-event-e1532524398949.jpg Conclusion We have observed from the above pitfalls that it’s easy to make LCM-GCD your friend. Since questions on LCM-GCD constitute an important part of Number Properties and are frequently tested on GMAT, it’s advisable to be proficient on this topic. Once you have gone through the above article and identified the potential pitfalls in LCM-GCD question, practice more questions on such concepts to prepare yourself better for the exam day. Hope that this article would be a ‘factor’ in your quant preparation and your joy is a ‘multiple’ of your quant score. Wish you a great GMAT journey! Other Relevant Articles Click here for more fresh questions and must-read articles on what to do and what not to do in GMAT Quant.

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3 Deadly Mistakes you must avoid in LCM-GCD Questions

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28 Mar 2019, 00:49

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Hey Everyone,

We've added 3 new practice questions in which you can apply your learnings of Number Properties.

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Hey Everyone,

We have posted the official solutions to the practice questions.

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Hey Everyone,

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Why the product of two number a and b equal to the product of gcd(a,b) and lcm(a,b)
Let say a and b are kp and kq where k is the hcf of a and b, also then a and b becomes co- prime so lcm becomes kab
Now product of two numbers = kp×kq
Product of hcf and lcm = k ×kab
Therefore product of two numbers is always equal to product of hcf and lcm

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Hey Everyone,

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HCF for more than 2 numbers, I have been using the school method and it works fine ( and fast).

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