At a certain corporation, the planning committee has 23 members

Question

At a certain corporation, the planning committee has 23 members and the finance committee has 20 members. If a total of 21 people are members of only one of the two committees, how many are members of both committees?

a) 3
b) 11
c) 15
d) 20
e) 22

A. 3
B. 11
C. 15
D. 20
E. 22

Bunuel · Accepted Answer

At a certain corporation, the planning committee has 23 members and the finance committee has 20 members. If a total of 21 people are members of only one of the two committees, how many are members of both committees?

a) 3
b) 11
c) 15
d) 20
e) 22

A. 3
B. 11
C. 15
D. 20
E. 22

This statement, "a total of 21 people are members of only one of the two committees," means that 21 people are members of one committee or the other, but not both.

Assuming x members belong to both committees, the number of members who belong only to the planning committee would be 23 - x, and the number of members who belong only to the finance committee would be 20 - x. Thus, we have:

(23 - x) + (20 - x) = 21

x = 11

Answer: B.

Souvik7 · Answer

Let x = only planning 
 Z = only finance 
 Y = both 
Then x+ z = 21
X+y = 23
Y+z =20

Solving for y = 11

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Archit3110 · Answer

solve using 2x2 matrix
---P----NP----total
F--- ----- b---20
NF-- a---- ----
total--23-- ---- --
given that a+b = 21
so
20-b= 23-a
we get
a-b=3
a+b=21
solve a = 12 and b = 9

---P----NP----total
F---11 ----- 9---20
NF-- 12---- ----
total--23-- ---- --

OPTION B 11

ruis · Answer

Can anyone please help me understand what I am missing here?

sayan640 · Answer

It would be

23 - x + 20 - x = 21
x=11

Fish181 · Answer

If you take 23 + 20 - BOTH = 21, you will find that BOTH = 22. The trick on this problem the testmakers want you to fall for is not accounting for the redundant count.

the group of 20 finance members have BOTH members and the group of 23 planning committee members have BOTH members counted for. Therefore the answer you receive here counts the BOTH amount twice. You have to divide by 2 to get the actual answer.

a191291r · Answer

This is an official GMAT question. I wasted a solid 4.6 minutes on this and got it wrong and rest of the mock went under the bus! Am I really bad reading or is this a poorly worded question? Would be grateful to have your opinions on this Bunuel KarishmaB

Quote:

If a total of 21 people are members of only one of the two committees.....

I interpreted this text as: 21 people are members of only one of the two committees, i.e., they are either members of planning committee or members of finance committee. Since only 20 members belong to finance committee, 21 people cannot be the members of only finance committee (since 21>20), therefore, these 21 must be members of ONLY the planning committee.

Finally, I had deduced these numbers:
N(P) = # of Planning committee = 23 (given)
N(P only) = # Planning committee ONLY = 21
N(F) # of Finance committee = 20 (given)

And hence, # of members in both committees must be = N(P)-N(P only) = 23-21 = 2 (NOT AN ANSWER CHOICE)

I even made this table and checked:

Show Spoiler

Attachment:

GMAT-Club-Forum-tn3g3o5j.png [ 7.48 KiB | Viewed 6723 times ]

MBAToronto2024 · Answer

KarishmaB  How would you solve it?

KarishmaB · Answer

One easy way is discussed by Bunuel above. Another is using the concept of instances and people. A person in only one set adds one instance to the total instances whereas a person in 2 sets adds 2 instances to the total instances (and a person in 3 sets adds 3 instances) 23 + 20 = 43 is the total number of instances. 21 of these come from people in only one set and account for 21 instances. 22 instances are left unaccounted for now. These must come from people in both sets and since each person here contributes 2 instances, there must be 11 people in both sets. Answer (B) Here are some interesting sets questions: https://youtu.be/rnqM1YCaLp8 https://youtu.be/18ZDLj7KMkc https://youtu.be/1RZdJTKCDYs

btsaami · Answer

1) Let a be the no. of members in only one team and b in both teams. We have to find b.
a+2b=20+23
2b=43-21
b=11. Hence, answer.

2) Let a be the number of members in only planning team and b only in finance.
a+b=21
23-a=20-b
a-b=3
Solving these equations we get, 2a=24 a=12. Hence, 23-12=11. Answer B

3) Use options.
A) we get 20+17 not equal to 21
B)11 we get 12+9=21. Hence, the answer.

Harshita2003 · Answer

This is how I got the solution. (I did get it wrong during the actual mock

) Let's assume that the number of members of both committee=x. Now we are given that: Planning committee members= 23 Finance committee member= 20 Members of only one committee (wither F or P)= 21 So we can deduce that total number of employees (assuming all participate in this)= member of only one of the two committees+ members of both committee 21+x= 23+20-x {F+P- (F intersection P)} 2x=43-21 2x=22 x=11. Hence B.

HarshavardhanR · Answer

https://gmatclub.com/forum/download/file.php?id=85617 --- Harsha GMAT-Club-Forum-k4dus0r2.png

vipsgmat · Answer

Here Given P = 23 ; F = 20 ; Also 21 are members of only 1 committee If we take x as common member for both committee Only P = 23-x Only F = 20-x Therefore only P + only F = 21 23 - x + 20 - x = 21 2x = 22 Hence x = 11 Hope this Helps !!

At a certain corporation, the planning committee has 23 members

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At a certain corporation, the planning committee has 23 members

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