Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Sep 1507:00 PM EDT
-09:00 PM EST
Elite scores are possible when you enroll in a powerful GMAT course, taught live online + 6 months access to TTP OnDemand video courses included! Class starts Tues/Thurs Sept. 15, 2026 - Nov. 15, 2027, 7:00pm-9:00pm EST
Sep 1808:00 PM PDT
-09:00 PM PDT
Video explanations + diagnosis of 10 weakest areas + 150+ short videos + study plan!
Sep 2107:00 PM EDT
-10:00 PM EDT
Boost your GMAT score in less than one month in a live online class + 6 months access to TTP OnDemand video courses included! Class starts Mon, Tues, Wed, Thur, Fri Sept. 21, 2026 - Oct. 9, 2027, 7:00pm-10:00pm EST
30 May 2024, 15:12
Kudos
Bookmarks
X: 910
Z: 1,350
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
87% (02:18) correct
13%
(02:43)
wrong
based on 1494
sessions
History
Date
Time
Result
Not Attempted Yet
Let X, Y, and Z denote the number of international students, in thousands, that Company U predicted would be studying in the United States (US) during the school years 2014–2015, 2019–2020, and 2024–2025, respectively. The average (arithmetic mean) of X, Y, and Z is 1,128, and Y = 1,124. Company U predicted that there would be more international students studying in the US during the 2024–2025 school year than during the 2014–2015 school year.
In the table, identify a value of X and a value of Z that are jointly consistent with the information provided. Make only two selections, one in each column.
In the table, identify a value of X and a value of Z that are jointly consistent with the information provided. Make only two selections, one in each column.
ID: 100364
| X | Z | |
| 910 | ||
| 995 | ||
| 1,1175 | ||
| 1,350 | ||
| 1,435 |
ShowHide Answer
Official Answer
X: 910
Z: 1,350
Solving this question helps.
Taking a timed set of similar questions in
GMAT Club Forum Quiz →
is even better.
30 May 2024, 23:38
Kudos
Bookmarks
guddo
It is not important that you just correctly answer an easy question, but that you answer it correctly in the least time frame.
The information that can be drawn is
- Z>X
- Y =1124
- X+Y+Z = 3*1128
Look for options that add up to 2260 = > 910 + 1350 = 2260
As Z>X, Z=1350 and X = 910
General Discussion
18 Sep 2024, 08:54
Kudos
Bookmarks
1. Let's draw a diagram of the values on a number line.
2. Because the average of X, Y, Z is 1128, then their (signed) distances to the average sum up to 0. We also know that Y = 1124.
3. We can write the following equation:
a + b + c = 0 \(\rightarrow\) (X - 1128) + (Y - 1128) + (Z - 1128) = 0 \(\rightarrow\) -1128 - 1128 + (X + Z) - 4 = 0 \(\rightarrow\) X + Z = 2260.
4. The only other information we have is that X < Z.
5. Now consider the possible answers: 910, 995, 1,175, 1350, 1435. Estimating them will make summation faster: 900, 1000, 1200, 1350, 1400. The closest sum to 2260 is 900 + 1350. The original sum would be 910 + 1350 = 2260, which works.
6. Our answer is X = 910 and Z = 1350.
Image_AverageDiagram.jpg [ 8.36 KiB | Viewed 8660 times ]
2. Because the average of X, Y, Z is 1128, then their (signed) distances to the average sum up to 0. We also know that Y = 1124.
3. We can write the following equation:
a + b + c = 0 \(\rightarrow\) (X - 1128) + (Y - 1128) + (Z - 1128) = 0 \(\rightarrow\) -1128 - 1128 + (X + Z) - 4 = 0 \(\rightarrow\) X + Z = 2260.
4. The only other information we have is that X < Z.
5. Now consider the possible answers: 910, 995, 1,175, 1350, 1435. Estimating them will make summation faster: 900, 1000, 1200, 1350, 1400. The closest sum to 2260 is 900 + 1350. The original sum would be 910 + 1350 = 2260, which works.
6. Our answer is X = 910 and Z = 1350.
Attachment:
Image_AverageDiagram.jpg [ 8.36 KiB | Viewed 8660 times ]
