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Let the total number beads in Container 1 and 2 be X and Y respectively.

Container 1:
Gold: Total = 1:6
So Gold = X/6.

Green:Total = 3/6
Green = Total/2=X/2

For Container 2:
Gold : Y = 4:8
Gold = Y/2


Green: Y = 1:8
Green = Y/8
Also given that:
X/6 + X/2 = Y/2 + Y/6
Solving we get 8X = 9Y
We need to align with options where X = 6k and Y = 8m
Options divisible by 6 are: 54 and 72
Options divisible by 8 are: 40, 64, 72
Plugging in we get only one way of possibility 8 (72) = 9 (64) = 576
So container 1: 72
Container 2: 64 are the ans IMO


Bunuel
Clara was assembling display trays using gold, green, and white beads from two containers.


In Container 1, the ratio of gold beads to green beads to white beads was 1 : 3 : 2.

In Container 2, the ratio of gold beads to green beads to white beads was 4 : 1 : 3.

Across the two containers combined, the total number of gold beads was equal to the total number of green beads.

Select for Container 1 the possible total number of beads in Container 1, and select for Container 2 the possible total number of beads in Container 2, that would be jointly consistent with the given information. Make only two selections, one in each column.
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Container 1: x:3x:2x -> total 6x -> must be multiple of 6
Container 2: 4y:y:3y -> total 8y

x+4y=3x+y
3y=2x
x=3y/2

Container 1: 6x=9y
Container 2: 8y

ratio=9y/8y=9/8

Container 1: must be multiple of 6 and 9
54 -> Container 2: 54/9 * 8 = 48 not in the list
72 -> Container 2: 72/9 * 8 = 64

Container 1 = 72
Container 2 = 64
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Container 1 - 72
Container 2 - 64

Sol
beads - Gold = x, green= y and white =z

Container 1 ratio 1:3:2
So 1:3:2 = 6x

Container 2 ratio 4:1:3
So 4:1:3 = 8y

Total number of gold beads = total number of white beads
so 1x + 4y = 3x+ 1y

3y =2x
So x/y = 3/2

We know that x= Total 1 / 6 , y = total 2 /8
so ( T1/6)/(T2/8) = 3/2
T1/T2 = 9/8
We know from statement T1 is multiple of 6 and T2 is multiple of 8 so our values can be only multiples of 6 or 8

so the only pair left is 72/64
Bunuel
Clara was assembling display trays using gold, green, and white beads from two containers.


In Container 1, the ratio of gold beads to green beads to white beads was 1 : 3 : 2.

In Container 2, the ratio of gold beads to green beads to white beads was 4 : 1 : 3.

Across the two containers combined, the total number of gold beads was equal to the total number of green beads.

Select for Container 1 the possible total number of beads in Container 1, and select for Container 2 the possible total number of beads in Container 2, that would be jointly consistent with the given information. Make only two selections, one in each column.
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ratio in C1: 1:3:2
ratio in C2: 4:1:3

X beads in C1: X must be divisible by 6
Y beads in C2: Y must be divisible by 8

X/6 + 4Y/8 = 3X/6 + Y/8
4X + 12Y = 12X + 3Y
8X = 9Y
Y = 8X/9

X must be divisible by 9 and 6, must be divisible by 18
X = 54, Y = 48 not possible
X = 72, Y = 64

Container 1 = 72 and Container 2 = 64
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Gold:Green:White
Container 1- 1:3:2. If total beads are x, then gold, green & white = x/6, x/2, x/3
Container 2- 4:1:3. If total beads are y, then gold, green & white = y/2, y/8, 3y/8

x/6 +y/2 = x/2+y/8
Solving gives y/x= 8/9

Hence when x= 45; y=8*45/9= 40
Bunuel
Clara was assembling display trays using gold, green, and white beads from two containers.


In Container 1, the ratio of gold beads to green beads to white beads was 1 : 3 : 2.

In Container 2, the ratio of gold beads to green beads to white beads was 4 : 1 : 3.

Across the two containers combined, the total number of gold beads was equal to the total number of green beads.

Select for Container 1 the possible total number of beads in Container 1, and select for Container 2 the possible total number of beads in Container 2, that would be jointly consistent with the given information. Make only two selections, one in each column.
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c1 = g:r:w = 1:3:2= x:3x:2x = total =6x
c2 =g:r:w = 4:1:3 = 4y:y:3y = total = 8y
now ATQ total green = total gold
therefore x+4y = 3x+y
x/ y= 3/2 =====> x =3k , y =2k
now C1 will have 6(3k) =18k
c2 = 8(2K) =16k
with the options we get c1 = 72 and c2 =64
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1+3+2=6 so number of beads in container 1 is multiple of 6, 6a
4+1+3=8 so number of beads in container 2 is multiple of 8, 8b

number of gold beads = 1*a+4*b
number of green beads = 3*a+1*b

a+4b=3a+b
3b=2a

number of beads in container 1 = 6a = 3*3b = 9b
number of beads in container 2 = 8b

container 2 = 8/9 * container 1

container 1 is multiple of 6 and multiple of 9.
there are two values, 54 and 72 but only 72 gives us a number for container 2 in the options (8/9)*72 = 64

Container 1: 72
Container 2: 64
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2 containers with gold, green and white beads

Container 1 -> Gold : Green : White = 1:3:2
Let total no of beads be 6x
=> Gold beads = x
=> Green beads = 3x
=> White beads = 2x

Container 2 -> Gold : Green : White = 4:1:3
Let total no of beads here be 8y
=> Gold beads = 4y
=> Green beads = y
=> White beads = 3y

We know that,
Total gold beads = Total green beads
=> x + 4y = 3x + y
=> 2x = 3y
=>x/y = 3/2 ----- 1

=> x = 3a and y = 2a for a positive integer a

=> Total number of beads in container 1 = 6x = 18a ------ 2
=> Total number of beads in container 2 = 8y = 16a ------- 3

With 1, 2 and 3
We can say from the given options

Container 1: 72
Container 2: 64
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c1 1:3:2
c2 4:1:3

c1 and c2 are the number of beads respectively

c1/6 + 4c2/8 = 3c1/6 + c2/8
c1/6 + c2/2 = c1/2 + c2/8
4c1 + 12c2 = 12c1 + 3c2
8c1 = 9c2

c2 = 8c1/9

c1 is divisible by 9: 81, 72, 54 or 45
but, as ratio of c1 is 1:3:2, then c1 is divisible by 6 too.

c1: 72 or 54
if c1=72, c2=64
if c1=54, c2=48, that is not in the list

c1=72, c2=64

Container 1 is 72 and Container 2 is 64
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C1: G (gold): g (green): w= 1:3:2
.: we can write, G=x, g=3x, w=2x

C2: G:g:w= 4:1:3
.: We can write, G=4y, g=y & w=3y

Now acc. to the question,
x+4y=3x+y
.: 3y=2x....(1)

.: y has to be factor of 2 and x has to be a factor of 3.

.: Total no of beads in C1,
A=3y/2+9y/2+3y=9y

We know y is Factor of 2,
.: A has a factor 18.
54 satisfies that.
.:A=54/72
.: Total no of beads in C2,
B=y+4y+3y=8y

.: We know y is factor of 2.
.: B has to be a multiple of 16.
Only 64 satifsies that.
.:B=64

But 9y>8y.
.: A=72
Bunuel
Clara was assembling display trays using gold, green, and white beads from two containers.


In Container 1, the ratio of gold beads to green beads to white beads was 1 : 3 : 2.

In Container 2, the ratio of gold beads to green beads to white beads was 4 : 1 : 3.

Across the two containers combined, the total number of gold beads was equal to the total number of green beads.

Select for Container 1 the possible total number of beads in Container 1, and select for Container 2 the possible total number of beads in Container 2, that would be jointly consistent with the given information. Make only two selections, one in each column.
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Bunuel
Clara was assembling display trays using gold, green, and white beads from two containers.


In Container 1, the ratio of gold beads to green beads to white beads was 1 : 3 : 2.

In Container 2, the ratio of gold beads to green beads to white beads was 4 : 1 : 3.

Across the two containers combined, the total number of gold beads was equal to the total number of green beads.

Select for Container 1 the possible total number of beads in Container 1, and select for Container 2 the possible total number of beads in Container 2, that would be jointly consistent with the given information. Make only two selections, one in each column.
Container C1 - Go : Gr : W = 1:3:2. Take commom multiplier as A
Total beads in C1 = 6A

Similarly taking multipler in C2 as B
Total beads in C2 = 8B

Based on conditions of gold and green beads being equal, we for eq.n
A + 4B = 3A + B
Hence A = 3B/2 and B = 2A/3

Beads in C1 = 6A - multiple of 6
We have only 2 options that are multiple of 6 which are 54 and 72

Taking beads in C1 = 54, 6A = 54
Hence A = 9 and B = 6
Beads in C2 = 8B = 48 which is not an option. ELIMINATE CONDITION

Take beads in C1 = 72
6A = 72, A = 12,
Hence B = 8
Beads in C2 = 8B = 64- which is an option

Answer: Beads in Container 1 = 72, Container 2 = 64
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IMO ANS is C1 = 72 & C2 = 8
Actually it is easy question but I got confused but this is super easy question if we focus properply.
SO here it says Gold = Green meaning x+4y = 3x+y meaning 2x = 3y
here c1 -> x & c2 -> y and total C1 = 6x & C2 = 8y so if we go to answer choice and just check which option satisfy both divide by 6 x and then by 8 y and also satisfying 2x = 3y so then x =12 72/6 =12 & y = 8 (64/8 = 8) and then 2x = 24 and same 3y = 24 so its easy but i took longer for me to get this. thanks!
Bunuel
Clara was assembling display trays using gold, green, and white beads from two containers.


In Container 1, the ratio of gold beads to green beads to white beads was 1 : 3 : 2.

In Container 2, the ratio of gold beads to green beads to white beads was 4 : 1 : 3.

Across the two containers combined, the total number of gold beads was equal to the total number of green beads.

Select for Container 1 the possible total number of beads in Container 1, and select for Container 2 the possible total number of beads in Container 2, that would be jointly consistent with the given information. Make only two selections, one in each column.
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gold: green : white

C1 -> 1:3:2
x+3x+2x = 6x

C2 -> 4:1:3
4y+y+3y=8y

gold total = green total
x+4y = 3x+y
2x=3y
x=3/2y

Possible number of
C1 -> 6x = 9y
C2 -> 8y = 12x

Then, we test from the option that align with factor of above equestion.

possible answer is
C1 = 6x -> 6*12 = 72
C2 = 8y -> 8*8 = 64

So, answer is 72 in container 1 and 64 in container 2
Bunuel
Clara was assembling display trays using gold, green, and white beads from two containers.


In Container 1, the ratio of gold beads to green beads to white beads was 1 : 3 : 2.

In Container 2, the ratio of gold beads to green beads to white beads was 4 : 1 : 3.

Across the two containers combined, the total number of gold beads was equal to the total number of green beads.

Select for Container 1 the possible total number of beads in Container 1, and select for Container 2 the possible total number of beads in Container 2, that would be jointly consistent with the given information. Make only two selections, one in each column.
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I haven`t gotten kudos for my explanation!?
anushree01
Let the total in C1 be p & C2 be q
Using gold equals greens combined we get -
p+q\4 = p\3+q
8p=9q
Thus 9 : 8 ratio

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anushree01
I haven`t gotten kudos for my explanation!?


No because your solution is incomplete.
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Container 1
The ratio (go:gr:w) is 1:3:2 ⭢ \(n+3n+2n = 6n\)

Container 2
The ratio (go:gr:w) is 4:1:3 ⭢ \(4x+x+3x = 8x\)

We know that the total number of gold beads is equal to the total number of green beads: \(n+ 4x = 3n+x\) ⭢ \(2n=3x\) ⭢ \(n = \frac{3}{2}x\)

So, the total number of beads in container 1 is: \(6*\frac{3}{2}x = 9x\).

The total number of beads in container 2 is: \(8x\).

The ratio between is: \(\frac{container 1}{container 2} = \frac{9x}{8x}\)

Therefore, we have to find two numbers that have 9/8 as ratio. The only possibility is 72 for container 1 and 64 for container 2.
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