gmatophobia
PS Question 1 - May 22 Of the four-digit positive integers that are greater than 4000, how many have three digits that are equal to each other and one digit that is not equal to the other three? A. 162 B. 215 C. 216 D. 240 E. 324 Source: GMATNinja | Difficulty: Medium
say a four digit number 4 _ _ _
the blanks can’t have all zeros (otherwise number will be Equal to 4000) and can’t have all digits as 4s, so there are a total of 8 equal numbers that can fill the blanks if all contraints are taken into consideration.
say a four digit number 5 _ _ _
note that here, although we can’t have all 5s, we can have rest all 9 possibilites
same goes for numbers starting with 6,7,8 and 9
so total numbers we collected so far = 8 + 9*5 = 53
UP next...
we can again have a four digit number say 4 _ _ _
but here, we can repeat the digit 4 three times and leave one blank with any of the remaining 9 possibilites. since the one unequal number can rotate between 3 blank spaces, we can say 9*3 ways we can fill in the blanks
and this remains true for numbers starting with 5,6,7,8,9.
hence total possibilities in this scenario = 9*3 * 6 = 162
Therefore, total four digit numbers = 53 + 162 = 215
option B