Tarek143
A bag contains some white and black balls. The probability of picking two white balls one after other without replacement from that bag is 14/33..
Then What will be the probability of picking two black balls from that bag if bag can hold maximum 15 balls only?
(White/Total)*(White-1/Total-1) = 14/33.....We need 2 sets of consecutive numbers to be equal to 14 and 33, respectively (OR a multiple of 14 and 33 respectively). 14 & 33 do not work. So, next is 28 & 66...nope. 42 & 99...42 works, 99 doesn’t....Next is, 56 & 132. This works (56 = 8 * 7, 132 = 12 * 11). It is also given that maximum number of total balls can be 15. So, it is safe to assume that there are 12 total balls and 8 of them are white. Which means, 4 of them are black......Probability of getting 2 black balls = (4/12)*(3/11) = 1/11