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Data Sufficiency Butler: October 2024
October 24DS 1DS 2
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Hey is anyone appearing for CAT 24 here?
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October 25DS 1DS 2
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does anyone know this DS question? I can’t find it online:

is (2^x)*(3^2w)*(5^(y+4)) = 4*(9^2)*(25^3)
(1) w=2
(2) x=y
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does anyone know this DS question? I can’t find it online:

is (2^x)*(3^2w)*(5^(y+4)) = 4*(9^2)*(25^3)
(1) w=2
(2) x=y

I could not find it either. However, pure algebraic questions are no longer a part of the DS syllabus of the GMAT.

DS questions in GMAT Focus encompass various types of word problems, such as:

  • Word Problems
  • Work Problems
  • Distance Problems
  • Mixture Problems
  • Percent and Interest Problems
  • Overlapping Sets Problems
  • Statistics Problems
  • Combination and Probability Problems

While these questions may involve or necessitate knowledge of algebra, arithmetic, inequalities, etc., they will always be presented in the form of word problems. You won’t encounter pure "algebra" questions like, "Is x > y?" or "A positive integer n has two prime factors..."

Check GMAT Syllabus for Focus Edition

You can also visit the Data Sufficiency forum and filter questions by OG 2024-2025, GMAT Prep (Focus), and Data Insights Review 2024-2025 sources to see the types of questions currently tested on the GMAT.

So, you can ignore this and similar questions.

Hope it helps.
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Bunuel
I could not find it either. However, pure algebraic questions are no longer a part of the DS syllabus of the GMAT.

DS questions in GMAT Focus encompass various types of word problems, such as:

  • Word Problems
  • Work Problems
  • Distance Problems
  • Mixture Problems
  • Percent and Interest Problems
  • Overlapping Sets Problems
  • Statistics Problems
  • Combination and Probability Problems

While these questions may involve or necessitate knowledge of algebra, arithmetic, inequalities, etc., they will always be presented in the form of word problems. You won’t encounter pure "algebra" questions like, "Is x > y?" or "A positive integer n has two prime factors..."

Check GMAT Syllabus for Focus Edition

You can also visit the Data Sufficiency forum and filter questions by OG 2024-2025, GMAT Prep (Focus), and Data Insights Review 2024-2025 sources to see the types of questions currently tested on the GMAT.

So, you can ignore this and similar questions.

Hope it helps.
thanks for the tips! Bunuel!
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Ten slips of paper, numbered 1 through 10, are placed in a bag. If three slips are chosen at random from the bag without replacement and one of the slips chosen is numbered 7, what is the sum of numbers on the three chosen slips of paper?

(1) The sum of two of the numbers chosen is 16.
(2) The sum of two of the numbers chosen is 14.

hey guys can anyone please explain me the statements and if B is sufficient why is not A? I saw the official solution but got a little confused, can someone please explain. Thank you in advance.
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Numbers are chosen without replacement. If sum is 14, one of the numbers cannot be 7 since 7 can be chosen only once. Therefore sum of other 2 numbers is 14. Total sum = 7+14=21. Hence B is sufficient.
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can you also please explain why A is not the option?

i mean why A is not correct?
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One of the 3 numbers picked is 7. Let the other two be "a" and "b".

(1) sum of two of the numbers is 16. Here, there are several possibilities.

For instance,
(7,9,2). 7+9 = 16. Overall sum is 18.
(7,9,5). 7+9 = 16. Overall sum is 21
(7,10,6). 10+6 = 16. Overall sum is 23.

Clearly Statement 1 is not sufficient.

(2) The sum of two of the numbers chosen is 14.

Here, we can be sure that 7 is not one of the 2 numbers whose sum is 14. Because for 7 + some number to give 14, the other number has to be 7 again. But we are drawing numbers without replacement. 7 again is not possible.

Hence, the sum of the OTHER TWO numbers (excluding the 7) is 14. a+b = 14

Then, the overall sum is (a+b+7) = 14+7 =21.

Hope this helps!
Harsha
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Hey guys, I’m a current student at ISB pursing my PGP. It was around this time when I was invited for an interview and I feel nostalgic of how much of effort did I take to know the right advices from students at ISB. I just wanted to make it easier for you guys.

Here’s my new instagram page where the class of 25 answers your FAQs. Get in touch with us and get your profile reviewed.



Do consider following us if you find it useful. It would help us grow.

Link : https://www.instagram.com/mbastoriesunplugged/



Regards

Anurag
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RiyaGangar
Numbers are chosen without replacement. If sum is 14, one of the numbers cannot be 7 since 7 can be chosen only once. Therefore sum of other 2 numbers is 14. Total sum = 7+14=21. Hence B is sufficient.
Thank you so Kuch Riya for this. Much grateful :)

HarshR9
One of the 3 numbers picked is 7. Let the other two be "a" and "b".

(1) sum of two of the numbers is 16. Here, there are several possibilities.

For instance,
(7,9,2). 7+9 = 16. Overall sum is 18.
(7,9,5). 7+9 = 16. Overall sum is 21
(7,10,6). 10+6 = 16. Overall sum is 23.

Clearly Statement 1 is not sufficient.

(2) The sum of two of the numbers chosen is 14.

Here, we can be sure that 7 is not one of the 2 numbers whose sum is 14. Because for 7 + some number to give 14, the other number has to be 7 again. But we are drawing numbers without replacement. 7 again is not possible.

Hence, the sum of the OTHER TWO numbers (excluding the 7) is 14. a+b = 14

Then, the overall sum is (a+b+7) = 14+7 =21.

Hope this helps!
Harsha
Finally understood. Just the explanation I was looking for.
Thank you very very much Harsh. God bless.
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