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Thanks for your response! What do you think about the question linked( mischa-drove-from-a-to-b-a-distance-of-100-miles-176883.html?srsltid=AfmBOoqweiOPnPL9trj94VretEdntiUUFbFZ5CWxEPAROp4GmXtfrfA8 )? Because of that the answer can be D, E

Check here: https://gmatclub.com/forum/bob-invested ... 96540.html Hope it helps.

There are total of 33 students in 3 rooms . There are 8 students in room A. There are 3/2 times as many students in room B than A . The rest are in room C. Ikra wants to give the students some candies. She already has 260 candies. How many more candies does she need to buy to distribute them evenly in each of the three sections? A) 50 B) 52 C) 54 D) none of these How to solve this math

we just need more 4 candies so the answer is (d) none of these?

question is asking to distribute the candies evenly in each of the three sections, so each section should be having equal candies, in 1st section we have 8, in 2nd we have 12 and in third we have 13 students, which means 8a = 12b = 13c = k, so we just need to find the lcm of (8,12,13) which is 312, so we need 312-260 = 52 candies more

It doesnt say all candies are to be distributed equally between students . So adding the options to 360 only 52 is divisible by 3. Hence that could be the answer

a+b+c+d+0.35 / 5 = 0.5 a+b+c+d+0.35 = 2.5 a+b+c+d = 2.15 Now assuming the next greatest value to 0.35 would be 0.36. And assuming that b=c=d which is 0.36 then a+ 0.36 +0.36 + 0.36 = 2.15 a= 2.15- 0.36*3 a= 1.07 Now making another assumption that b=c=d=0.35 then also a + 0.35*4 =2.5 a = 1.1 and hence the greatest value of amongst the 5 cannot be greater than 1.1. D D should be the answer as per me. (I could be wrong guys!!!!!!!!)

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