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10 Jun 2025, 01:14
Kudos
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Yea I read it wrong 😅
10 Jun 2025, 04:55
Kudos
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The integer 120 has many factorizations. For example, 120 = (2)(60), 120 = (3) (4)(10), and
120 = (–1)(–3)(4)(10). In how many of the factorizations of 120 are the factors consecutive
integers in ascending order?
any other way than brute force to do this?
120 = (–1)(–3)(4)(10). In how many of the factorizations of 120 are the factors consecutive
integers in ascending order?
any other way than brute force to do this?
10 Jun 2025, 06:14
Kudos
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deadguy1729
The integer 120 has many factorizations. For example, 120 = (2)(60), 120 = (3) (4)(10), and
120 = (–1)(–3)(4)(10). In how many of the factorizations of 120 are the factors consecutive
integers in ascending order?
any other way than brute force to do this?
120 = (–1)(–3)(4)(10). In how many of the factorizations of 120 are the factors consecutive
integers in ascending order?
any other way than brute force to do this?
Check here: https://gmatclub.com/forum/the-integer- ... 22417.html
