Practice Tech currently offers 2,000 courses per year, and Jameson Voc

Question

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Practice Tech currently offers 2,000 courses per year, and Jameson Vocational currently offers 3,200 courses per year. The number of courses offered by each school increases each year at a constant rate. If each of these schools continues to offer an increased number of courses annually at its constant rate, in three years both schools will offer the same number of courses for the first time. Each year after three years, Practice Tech will offer more courses per year than Jameson Vocational. In the table below, identify the rates of increase, in annual courses offered, for each school that together meet the course offering forecasts described above. Select only one option in each column.

Archit3110 · Accepted Answer

2000+3x=3200+3y
(x-y)=400
x>y
x=800 & y =400

bhagyajeet.sahu · Answer

Can some explain the solution?

Maheshkv · Answer

Hi  bhagyajeet.sahu ,

As the question says, if practice and jameson both increase at constant rate in 3 yrs time they both would be same.

So practice rate of increase be x courses/yr then after 3 yrs= 2000+ 3*x
similarly for jameson let rate of increase be y courses/yr then after 3 yrs= 3200+3*y

after 3 yrs both are same so 2000 + 3x = 32000 + 3y => x - y = 400

Final x and y which satisfy the criteria from the given options, they are x = 800 and y = 400.

Hope this clarifies!

Sajjad1994 · Answer

Official Explanation

If Practice Tech increases its course offerings by 800 courses per year, in three years it will offer 4,400 courses per year. If Jameson Vocational increases course offerings by 400 courses per year, in three years it will offer 4,400 courses per year as well. After the three-year mark, Practice Tech will offer more courses per year than Jameson Vocational.

Purnank · Answer

Assuming Practice Tech currently increasing at rate of x and Jameson Vocational currently increasing at rate of y.
and both of these rates remain constant through out.

Given - in three years both schools will offer the same number of courses for the first time.
Therefore, 
2000 + 3x = 3200 + 3y
3x - 3y = 1200
x - y = 400
x = y + 400
Put values for y and check for x if its there table bingo thats our answer.
y = 250,   400  , 540, 600, 760, 800
So,
x = 650,   800  , 940, 1000, 1160, 1200.

SA116 · Answer

Cant we use the formula 2000 ^3 = 3200 ^3 ?. if yes then how to arrive at the solution.

Purnank · Answer

No its not that way please refer to the solution posted above.

Sunny9681 · Answer

I simply used the options to solve this. Since the difference between the 2 course is 1200. We need to select the option for which the difference is 1200 for 3 years.

bumpbot · Answer

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Practice Tech currently offers 2,000 courses per year, and Jameson Voc

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PRACTICE TECH	JAMESON VOCATIONAL	RATE OF INCREASE (COURSES PER YEAR)
		250
		400
		540
		600
		760
		800

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