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problem solving

Author Message
Senior Manager
Joined: 18 Sep 2009
Posts: 356
Followers: 3

Kudos [?]: 489 [0], given: 2

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04 Oct 2009, 07:33
00:00

Difficulty:

(N/A)

Question Stats:

100% (01:55) correct 0% (00:00) wrong based on 4 sessions

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On a certain transatlantic crossing, 20 percent of a shipâ€™s passengers held round-trip tickets and also took their cars abroad the ship. If 60 percent of the passengers with round-trip tickets did not take their cars abroad the ship, what percent of the shipâ€™s passengers held round-trip tickets?

A. 33 1/3%
b. 40%
C. 50%
D. 60%
E. 66 2/3

Thanks
Director
Joined: 01 Apr 2008
Posts: 882
Name: Ronak Amin
Schools: IIM Lucknow (IPMX) - Class of 2014
Followers: 30

Kudos [?]: 707 [0], given: 18

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04 Oct 2009, 08:42
RTT = passengers with round trip ticket
C = passengers with cars aboard.
T = total passengers

20%T ==> passengers with RTT and C ( that is BOTH )
60%RTT don't have cars ==> 40%RTT have cars ( that is BOTH )

so, BOTH = 20%T = 40%RTT
Quest asks us to find RTT/T = 20/40 = 50%
Manager
Joined: 05 Mar 2011
Posts: 145
Followers: 0

Kudos [?]: 55 [0], given: 3

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03 Dec 2011, 17:55
pick numbers to solve this-its easier thn dng algebra
Senior Manager
Joined: 13 May 2011
Posts: 312
WE 1: IT 1 Yr
WE 2: Supply Chain 5 Yrs
Followers: 21

Kudos [?]: 264 [0], given: 11

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04 Dec 2011, 02:46
Using the Matrix,

Given, .4X= 20
therefore, X= 50
Attachments

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Re: problem solving   [#permalink] 04 Dec 2011, 02:46
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