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cruisingjerry
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Properties of Intergers Question 15 Oct 2013, 01:35
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Can someone help me what I am missing here? It seems easy question, but I just can't see what I should look for.

If x is an integer and y =3x+2, which of the following CANNOT be a divisor of y?

A) 4
B) 5
C) 6
D) 7
E) 8

No idea what to look for...
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KarishmaB
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Properties of Intergers Question 15 Oct 2013, 02:58
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cruisingjerry
Can someone help me what I am missing here? It seems easy question, but I just can't see what I should look for.

If x is an integer and y =3x+2, which of the following CANNOT be a divisor of y?

A) 4
B) 5
C) 6
D) 7
E) 8

No idea what to look for...
Show more

What is the information given by y = 3x + 2 (where x is an integer)? It tells us that y is 2 more than a multiple of 3. This means y cannot be a multiple of 3.
Hence y is certainly not a multiple of 6 because for that to happen y must be a multiple of 3 as well as 2.

Answer (C)
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cruisingjerry
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Properties of Intergers Question 15 Oct 2013, 21:35
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VeritasPrepKarishma
cruisingjerry
Can someone help me what I am missing here? It seems easy question, but I just can't see what I should look for.

If x is an integer and y =3x+2, which of the following CANNOT be a divisor of y?

A) 4
B) 5
C) 6
D) 7
E) 8

No idea what to look for...

What is the information given by y = 3x + 2 (where x is an integer)? It tells us that y is 2 more than a multiple of 3. This means y cannot be a multiple of 3.
Hence y is certainly not a multiple of 6 because for that to happen y must be a multiple of 3 as well as 2.

Answer (C)
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Thank you very much. :)
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abhinav11
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Properties of Intergers Question 15 Oct 2013, 23:43
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cruisingjerry
Can someone help me what I am missing here? It seems easy question, but I just can't see what I should look for.

If x is an integer and y =3x+2, which of the following CANNOT be a divisor of y?

A) 4
B) 5
C) 6
D) 7
E) 8

No idea what to look for...
Show more

Whenever I don't have any idea what to look for I use hit and trial , please see if it suits you, you can use the same as well.

My approach is to use hit and trial and I always start with B,C, D options, it works most of the times(Personal Experience).

You just need to find any value of x for which y is divisible by given options .

No value exist of x for which y is divisible by 6 hence answer C.

Lengthy surely , but effective most of the times.

Regards,
Abhinav