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# PS: Probability

Author Message
Director
Joined: 01 Apr 2008
Posts: 830
Name: Ronak Amin
Schools: IIM Lucknow (IPMX) - Class of 2014

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24 Mar 2009, 09:00
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

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From a group of 3 boys and 3 girls, 4 children are to be randomly selected. What is the
probability that equal numbers of boys and girls will be selected?
A.1/10
B. 4/9
C.1/2
D.3/5
E.2/3

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Manager
Joined: 05 Jan 2009
Posts: 73

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24 Mar 2009, 14:51
IMO: D.

P=3/6*2/5*3/4*2/3=1/10. Now, order does not matter among BBGG. 4!/2!*2!=6.

P=6/10=3/5
Intern
Joined: 28 Mar 2008
Posts: 34

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24 Mar 2009, 14:53
D.3/5

3C2*3C2/6C4 = 9/15 = 3/5

--== Message from GMAT Club Team ==--

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If you would like to discuss this question please re-post it in the respective forum. Thank you!

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Re: PS: Probability   [#permalink] 24 Mar 2009, 14:53
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