Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Here is how I would approach this. (1) Use the distance formula and find the length of the sides. (2) Use the triangle formula (A=b*h) to calculate the area. Note that the height of the triangle is found using the right angle perpendicular.

Yes. it should be 6.. D This question can not be solved in 2 mins.. I guess. I used the following way :

1 ) distance between the points ( you will have to do this verbally as we wont have much time ) L(1, 3), M(5, 1), and N(3, 5) are 2v5 , 2v5 and 2v2 .. so its an isosceles triangele

2 ) now considering 2v2 as the base, the height will be = v[ (2v5)^2 - (v2)^2 ] { V2- as it is the half of the base } = 3v2

Method I: When the points are plotted, and when the triangle is inscribed in a square, the side of the square is 4.

Area of required triangle = Area of sq- (area of 3 rt. triangles) = 16- (4+2+4) = 6

Method 2:

To find the area of the triangle when all the sides are gives as: a,b,c. Semi-perimeter of the triangle s = (a+b+c)/2 and area A = sqrt[s(s-a)(s-b)(s-c)]

Here a, b, c are 2sqrt(2), 2sqrt(5) and 2sqrt(5). Area = sqrt[ (2V5+V2) (2V5-V2) (V2) (V2)] =sqrt(18*2) =6

Hence D
_________________

To find what you seek in the road of life, the best proverb of all is that which says: "Leave no stone unturned." -Edward Bulwer Lytton

Last edited by leonidas on 13 Sep 2008, 18:07, edited 2 times in total.

ssandeepan.... Thanks....I made a mistake earlier- used 2V2 instead of 2V5.... It will suck if I made these kind of mistakes in the real test. I corrected that and re-posted.
_________________

To find what you seek in the road of life, the best proverb of all is that which says: "Leave no stone unturned." -Edward Bulwer Lytton

Find the area of the square and then subrtract out the area of the 3 right triangles with the remainder being the area of the triangle in question.

I found the area of the square [yellow + orange] and then subtracted out the individual yellow triangles. Much easier since all 3 yellow tiangles are right triangles.

Attachment:

AreaOfTriangle.jpg [ 56.59 KiB | Viewed 849 times ]

_________________

------------------------------------ J Allen Morris **I'm pretty sure I'm right, but then again, I'm just a guy with his head up his a$$.

Find the area of the square and then subrtract out the area of the 3 right triangles with the remainder being the area of the triangle in question.

I found the area of the square [yellow + orange] and then subtracted out the individual yellow triangles. Much easier since all 3 yellow tiangles are right triangles.

Attachment:

AreaOfTriangle.jpg

Nice diagram!!!!! I guess I was too lazy to draw one.......
_________________

To find what you seek in the road of life, the best proverb of all is that which says: "Leave no stone unturned." -Edward Bulwer Lytton