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29 Apr 2021, 00:35
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Solution:
First pipe - Fills 1/2 tank in 3 hours =>1 full tank in 6 hours
Second pipe- Fills 2/3 rd tank in 6 hours = > 1 full tank in 6 * (3/2) = 9 hours
LCM(6,9) = 18 => Let the capacity of the tank be 18 units
=> Efficiency of first pipe = 18/6 = 3 units/hour
=>Efficiency of second pipe = 18/9 = 2 units/hour
Working together, they fill 3+2 =5 units/hour
=> They would take 18/5 = 3.6 hours (option b)
Devmitra Sen
GMAT SME
First pipe - Fills 1/2 tank in 3 hours =>1 full tank in 6 hours
Second pipe- Fills 2/3 rd tank in 6 hours = > 1 full tank in 6 * (3/2) = 9 hours
LCM(6,9) = 18 => Let the capacity of the tank be 18 units
=> Efficiency of first pipe = 18/6 = 3 units/hour
=>Efficiency of second pipe = 18/9 = 2 units/hour
Working together, they fill 3+2 =5 units/hour
=> They would take 18/5 = 3.6 hours (option b)
Devmitra Sen
GMAT SME
12 May 2021, 00:53
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rite2deepti
Answer: Option B
Video solution by GMATinsight
13 May 2021, 07:17
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rate of pipe 1 ; 1/2 capacity in 3 hours so in 6 hours 1 unit
and rate of pipe 2 ; 2/3 in 6 hrs ; if capacity if 3 so per unit 3 hrs and full will be 9 hours
combined rate ; 1/6+1/9 ; 54/15 ; 3.6
option B
and rate of pipe 2 ; 2/3 in 6 hrs ; if capacity if 3 so per unit 3 hrs and full will be 9 hours
combined rate ; 1/6+1/9 ; 54/15 ; 3.6
option B
rite2deepti
