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Q. A seller sold two shoes at the same selling price. If the percentag
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Q. A seller sold two shoes at the same selling price. If the percentage profit on one of the shoes was 30% and the percentage loss on the other shoe was 30%, find the overall percentage profit or loss made by the seller. A. 3% loss B. 3% profit C. 9% loss D. 9% profit E. No profit no Loss Thanks, Saquib Quant Expert eGMATTo read all our articles: Must read articles to reach Q51
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Re: Q. A seller sold two shoes at the same selling price. If the percentag
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Re: Q. A seller sold two shoes at the same selling price. If the percentag
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20 Mar 2017, 07:10
EgmatQuantExpert wrote: Q. A seller sold two shoes at the same selling price. If the percentage profit on one of the shoes was 30% and the percentage loss on the other shoe was 30%, find the overall percentage profit or loss made by the seller. A. 3% loss B. 3% profit C. 9% loss D. 9% profit E. No profit no Loss Thanks, Saquib Quant Expert eGMATRegister for our Free Session on Number Properties (held every 3rd week) to solve exciting 700+ Level Questions in a classroom environment under the realtime guidance of our Experts Let he sold each shoes for Rs 100 then for first shoe ,let original price be x then @ 30% profit x(1+30/100)= 100 x~ Rs 77 original price of first shoe = Rs77 similarly for second shoe let original price be y y(130/100) =100 y~ 142 original price of first shoe = Rs142 so total of original price(CP)= 77+142 = 219 but he sold both for(SP) =Rs 100 +100= 200 Now its clear ,he is making loss Let a be loss % then 219(1a/100) =200 a =~9 he is making loss of 9% Ans C



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Re: Q. A seller sold two shoes at the same selling price. If the percentag
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20 Mar 2017, 08:57
EgmatQuantExpert wrote: Q. A seller sold two shoes at the same selling price. If the percentage profit on one of the shoes was 30% and the percentage loss on the other shoe was 30%, find the overall percentage profit or loss made by the seller.
A. 3% loss B. 3% profit C. 9% loss D. 9% profit E. No profit no Loss
The percentages will be 1.3x and .7y where x and y are cost prices respectively. So choosing a selling price that's LCM of 13 and 7  let the SP be 91. 1.3x = 91. x=70. .7y = 91. y=130. Hence the total CP = x+y=200. SP = 91+91=182. Loss% = 200182/200 = 9%. Hence C Cheers!



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Re: Q. A seller sold two shoes at the same selling price. If the percentag
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20 Mar 2017, 09:29
EgmatQuantExpert wrote: Q. A seller sold two shoes at the same selling price. If the percentage profit on one of the shoes was 30% and the percentage loss on the other shoe was 30%, find the overall percentage profit or loss made by the seller.
A. 3% loss B. 3% profit C. 9% loss D. 9% profit E. No profit no Loss Overall percentage profit or loss = \( (30)^2/100\) Or, Overall percentage profit or loss = \( 9\) Thus, answer must be (C) 9% loss...
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Re: Q. A seller sold two shoes at the same selling price. If the percentag
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20 Mar 2017, 10:10
Let the cost price of the two shoes be x and y x was sold at 30% profit and y was sold at 30% loss. And the selling prices were the same (Let the selling price be s)
so s=x(\(1+\frac{30}{100}\))=y(\(1\frac{30}{100}\)) 13x=7y y=\(\frac{13}{7}\)x
Let x = 70 y=130 and s=70(\(1+\frac{30}{100}\))=\(\frac{(70*130)}{100}\)=91
Total selling price = 2*91=182 Total cost price = x+y=200
Since the cost price is less than the selling price, the seller incurred loss. Loss % =\(\frac{200182}{200}*100\) = \(\frac{(18*100)}{200}\)=9
Answer C



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Re: Q. A seller sold two shoes at the same selling price. If the percentag
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21 Mar 2017, 02:46
EgmatQuantExpert wrote: Q. A seller sold two shoes at the same selling price. If the percentage profit on one of the shoes was 30% and the percentage loss on the other shoe was 30%, find the overall percentage profit or loss made by the seller. A. 3% loss B. 3% profit C. 9% loss D. 9% profit E. No profit no Loss Thanks, Saquib Quant Expert eGMATRegister for our Free Session on Number Properties (held every 3rd week) to solve exciting 700+ Level Questions in a classroom environment under the realtime guidance of our Experts let the selling price for both shoes be 100 for first the profit is 30%. therefore the CP = 100/1.3 = 76.92 for second the loss is 30%. therfore the CP = 100/0.7 = 142.85 total CP = 219.77 SP = 200 loss = 19.77 loss% = 19.77/200 . 100 = 9.88% or 9% loss
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Re: Q. A seller sold two shoes at the same selling price. If the percentag
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09 Feb 2018, 10:49
Let selling price be 91 (LCM of 13 and 7)
Shoe1 : 1.3 s1 = 91 => s1 = 70 Shoe2 : 0.7 s2 = 91 => s2 = 130
Profit or loss = 182/(130+70) = 91/100 => 9% loss (C)



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Re: Q. A seller sold two shoes at the same selling price. If the percentag
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23 Sep 2018, 15:50
EgmatQuantExpert wrote: Q. A seller sold two shoes at the same selling price. If the percentage profit on one of the shoes was 30% and the percentage loss on the other shoe was 30%, find the overall percentage profit or loss made by the seller.
A. 3% loss B. 3% profit C. 9% loss D. 9% profit E. No profit no Loss We can let the selling price of each shoe = $91. Thus, for the shoe that has 30% profit, the purchasing cost, x, can be determined by the equation: x(1.3) = 91 x = 91/1.3 = 70 Likewise, for the shoe that has 30% loss, the purchasing cost, y, can be determined by the equation: y(0.7) = 91 x = 91/0.7 = 130 Therefore, the total cost of the two shoes is 70 + 130 = $200 and the total revenue of the two shoes is 2(91) = $182. Therefore, the percent change is (182  200)/200 = 18/200 = 9%, i.e., the seller has a 9% loss. Answer: C
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26 Sep 2018, 22:03
Hi All, We're told that a seller sold two shoes at the SAME selling price; the percentage profit on one of the shoes was 30% and the percentage loss on the other shoe was 30%. We're asked for the overall percentage profit or loss made by the seller. This question can be solved by TESTing VALUES  and the answer choices are sufficiently 'spread out' that we don't have to worry about trying to find the 'perfect' numbers to TEST: the number 100 will be fine. To start, we have to create two equations to figure out the individual profit and loss described (we can set the selling price for each shoe at $100): The shoe that was sold for a 30% profit: X + .3X = $100 1.3X = $100 X = 100/1.3 = 1000/13 = about $77 > this is a PROFIT of $100  $77 = $23 The shoe that was sold for a 30% loss: Y  .3Y = $100 .7Y = $100 Y = 100/.7 = 1000/7 = about $143 > this is a LOSS of $143  $100 = $43 Thus, the 'net' of the two sales is $23  $43 =  $20 > a LOSS of about $20 Since the total sale price of the two shoes is $100 + $100 = $200, we know that $20 is 10%, so the LOSS was about a 10% loss. There's only one answer that makes sense... Final Answer: GMAT assassins aren't born, they're made, Rich
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Re: Q. A seller sold two shoes at the same selling price. If the percentag
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14 Nov 2018, 09:00
When 2 items are sold at same SP, suppose x, one at a profit of p% other at a loss of p%.
There is an overall loss given by p^2/100 %.
Here we have p = 30%.
Loss = 30*30/100 % = 9%



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Re: Q. A seller sold two shoes at the same selling price. If the percentag
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15 Nov 2018, 01:02
seller sold two shoes at the same selling price. If the percentage profit on one of the shoes was 30% and the percentage loss on the other shoe was 30%, find the overall percentage profit or loss made by the seller? Original price of shoes be x & y Selling price be p P = 1.3x & P = 0.7y 1.3x = 0.7y y = 13/7 x
Original total cost = x+y = 20/7x Total selling price ,= 1.3x+0.7y = 26/10x
Overall profit/loss =(26/10  20/7) / (20/7) = 18/200 = 9/100 Hence Loss of 9% (C)
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Re: Q. A seller sold two shoes at the same selling price. If the percentag
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15 Nov 2018, 03:24
Assume SP = 100 for both
CP for first at profit of 30% 100 = (1 + (30/100))*x x = 100/1.3 ~ 77
CP for second at loss of 30% 100 = (1  (30/100))*x x = 100/0.7 ~ 142.85
Total SP = 200 Total CP = 77 + 142.85 = 219.85 Loss = (219.85200)/2 = 9.875% i.e. 9% loss
Hence C



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Q. A seller sold two shoes at the same selling price. If the percentag
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15 Nov 2018, 08:33
Hi fskilnik, PLease help me with this problem. my method is bit long but I want to find the flaw in my reasoning Let SP=X, CP=Y therefore 30 = ((xy)/y)*100 100x100y=30y =>130y =100x=>x=13y/10 => Total SP (x)= 2x = 2(13y/10)= 13y/5 2nd case, Let CP = y1 ((y1x)*100)/y1 = 30 => (100 y1  100x)/y1 = 30 => 70y1= 100(13y/10) => 70y1 = 130y y1= 130y/70= 13y/7 => Total CP = y + 13y/7 = 20y/7 Overall loss %, ((20y/713y/5)/y) comes to aprrox 25%.. where have I gone wrong?..pls help



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Q. A seller sold two shoes at the same selling price. If the percentag
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15 Nov 2018, 08:50
Hi yashna36, So you were right till the last step You just mixed up what you considered as Total CP & Total SP P/L = \(\frac{(CPSP)}{CP}\) (In your formula the denominator of Total Cost Price was incorrect) CP = \(\frac{20y}{7}\) SP = \(\frac{13y}{5}\) P/L = (\(\frac{20y}{7}\)  \(\frac{13y}{5}\))/\(\frac{20y}{7}\) = \(\frac{9y}{100y}\) = 9% loss as CP>SP



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Re: Q. A seller sold two shoes at the same selling price. If the percentag
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15 Nov 2018, 09:09
eabhgoy, oh yes yes!!silly silly mistake.. denominator had to be the total CP. Thankyou so much



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Re: Q. A seller sold two shoes at the same selling price. If the percentag
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15 Nov 2018, 09:22
yashna36 wrote: Hi fskilnik, PLease help me with this problem. my method is bit long but I want to find the flaw in my reasoning Let SP=X, CP=Y therefore 30 = ((xy)/y)*100  where have I gone wrong?..pls help It seems (from the posts above) your doubts are gone. Thank you for helping yashna36, eabhgoy! Regards, Fabio.
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