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Since \(2 < x < 4\), test values between 2 and 4 in both quantities to seewhich quantity is larger for each example. On Quantitative Comparison questions, try to prove (D), or at least test whether it’s possible.
If \(x = 2.5\), Quantity \(A=\frac{2.5-3}{-2.5}=\frac{-0.5}{-2.5}=\frac{5}{25}=\frac{1}{5}\) and Quantity \(B=\frac{3-2.5}{-2.5}=\frac{0.5}{-2.5}=\frac{-5}{25}=\frac{-1}{5}\). In this case, Quantity A is greater.
Before just randomly trying other values between 2 and 4, try to strategize: is there an example in which Quantity B is greater? Since the two quantities have the same denominator, focus on the numerators. \(x – 3\) is positive when \(x > 3\) and negative when \(x < 3\). Since the first number tested was less than 3, next try something greater than 3.
If \(x = 3.5\), Quantity \(A=\frac{3.5-3}{-3.5}=\frac{0.5}{-3.5}=\frac{-5}{35}=\frac{-1}{7}\) and Quantity \(B=\frac{3-x}{-x}=\frac{3-3.5}{-3.5}=\frac{-0.5}{-3.5}=\frac{5}{35}=\frac{1}{7}\). In this case, Quantity B is greater. (Note: you could have stopped calculating the exact values of Quantity A and Quantity B for this example once it became clear that Quantity A was negative and Quantity B was positive.)
Alternatively, it would also be strategic to think about what number, if any, could make the two quantities equal. If \(x = 3\), Quantity A = Quantity B = 0, because both numerators will be 0, and 0 divided by any non-zero number is just 0.
Since Quantity A is greater than Quantity B for some values of x between 2 and 4, but Quantity B is greater than Quantity A for other values of x between 2 and 4, the relationship cannot be determined from the information given.
Answer: D