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05 Jan 2022, 02:30
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
77% (00:55) correct
23%
(00:57)
wrong
based on 43
sessions
History
Date
Time
Result
Not Attempted Yet
Rectangle EFGH has an area three times that of rectangle ABCD. What is the length of side FG?
A. 6
B. 12
C. 18
D. 24
E. 30
Attachment:
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05 Jan 2022, 05:13
Kudos
Bookmarks
Bunuel
Area of rectangle = Length*Width.
Width of rectangle ABCD = root(25-16) = 3. |Using pythogorus theoreum.
Area of rectangle ABCD = 4*3 = 12.
Area of EFGH = 3*12 = 36.
Area of EFGH = 2*Length = 36
Length = 18
C is the answer.
06 Jan 2022, 01:12
Kudos
Bookmarks
IMO C:
We can find Side BC = 3 (by Pythagoras theorem)
Now,
Given, Area Of EFGH = 3 x Area of ABCD
2 x FG = 3 x 4 x 3
FG = 18
We can find Side BC = 3 (by Pythagoras theorem)
Now,
Given, Area Of EFGH = 3 x Area of ABCD
2 x FG = 3 x 4 x 3
FG = 18
